SQL：如何在忽略时间的情况下比较日期？

Question

如何在忽略时间的情况下比较时间戳的日期？

我只想比较月/日/年。例如：

select * from Batch
where openingtime <> closingtime

问题是，这将显示太多批次，因为它将包括OpeningTime和ClosingTime仅在一天中的时间不同的批次：

OpeningTime = 2010-07-07 11:19:29.000

ClosingTime = 2010-07-07 19:19:22.000

Answer 1

将两个时间戳都转换为日期

对于SQL Server

Select * 
from Batch 
where cast(openingtime as date) <> cast(closingtime as date)

对于Oracle

Select * 
from Batch 
where trunc(openingtime) <> trunc(closingtime)

Answer 2

另一种方式

Select * from Batch where      
CONVERT(VARCHAR(10),openingtime,110<>CONVERT(VARCHAR(10),closingtime,110)

Answer 3

Select * from Batch where      
CONVERT(VARCHAR(10),openingtime,110)<>CONVERT(VARCHAR(10),closingtime,110)

**There will be a closing bracket** @Miyamoto Musashi