我想知道在Rails中解析文本查询的最佳方法是,允许用户包含逻辑运算符吗?
我希望用户能够输入其中任何一个或等效的内容:
source.include_exts = py, png, ... , gif
理想情况下,我们可以通过括号来表示更复杂的操作顺序,但这不是必需的。
是否有支持此内容的宝石或图案?
答案 0 :(得分:7)
这是一种可能但效率低下的方法:
user_input = "jon myers AND gmail AND smith OR goldberg OR MOORE"
terms = user_input.split(/(.+?)((?: and | or ))/i).reject(&:empty?)
# => ["jon myers", " AND ", "gmail", " AND ", "smith", " OR ", "goldberg", " OR ", "MOORE"]
pairs = terms.each_slice(2).map { |text, op| ["column LIKE ? #{op} ", "%#{text}%"] }
# => [["column LIKE ? AND ", "%jon myers%"], ["column LIKE ? AND ", "%gmail%"], ["column LIKE ? OR ", "%smith%"], ["column LIKE ? OR ", "%goldberg%"], ["column LIKE ? ", "%MOORE%"]]
query = pairs.reduce([""]) { |acc, terms| acc[0] += terms[0]; acc << terms[1] }
# => ["column LIKE ? AND column LIKE ? AND column LIKE ? OR column LIKE ? OR column LIKE ? ", "%jon myers%", "%gmail%", "%smith%", "%goldberg%", "%MOORE%"]
Model.where(query[0], *query[1..-1]).to_sql
# => SELECT "courses".* FROM "courses" WHERE (column LIKE '%jon myers%' AND column LIKE '%gmail%' AND column LIKE '%smith%' OR column LIKE '%goldberg%' OR column LIKE '%MOORE%' )
然而,正如我所说,像这样的搜索是非常低效的。我建议您使用全文搜索引擎,例如Elasticsearch。
答案 1 :(得分:4)
我在Sinatra应用程序中使用这样的解析器,因为查询往往很复杂我生成纯SQL而不是使用activerecords选择方法。 如果你可以使用它,请随意..
你这样使用它,class_name是表示表的activerecord类,params是要解析的字符串的散列,结果作为Json发送到浏览器 例如
generic_data_getter (Person, {age: ">30",name: "=John", date: ">=1/1/2014 <1/1/2015"})
def generic_data_getter (class_name, params, start=0, limit=300, sort='id', dir='ASC')
selection = build_selection(class_name, params)
data = class_name.where(selection).offset(start).limit(limit).order("#{sort} #{dir}")
{:success => true, :totalCount => data.except(:offset, :limit, :order).count, :result => data.as_json}
end
def build_selection class_name, params
field_names = class_name.column_names
selection = []
params.each do |k,v|
if field_names.include? k
type_of_field = class_name.columns_hash[k].type.to_s
case
when (['leeg','empty','nil','null'].include? v.downcase) then selection << "#{k} is null"
when (['niet leeg','not empty','!nil','not null'].include? v.downcase) then selection << "#{k} is not null"
when type_of_field == 'string' then
selection << string_selector(k, v)
when type_of_field == 'integer' then
selection << integer_selector(k, v)
when type_of_field == 'date' then
selection << date_selector(k, v)
end
end
end
selection.join(' and ')
end
def string_selector(k, v)
case
when v[/\|/]
v.scan(/([^\|]+)(\|)([^\|]+)/).map {|p| "lower(#{k}) LIKE '%#{p.first.downcase}%' or lower(#{k}) LIKE '%#{p.last.downcase}%'"}
when v[/[<>=]/]
v.scan(/(<=?|>=?|=)([^<>=]+)/).map { |part| "#{k} #{part.first} '#{part.last.strip}'"}
else
"lower(#{k}) LIKE '%#{v.downcase}%'"
end
end
def integer_selector(k, v)
case
when v[/\||,/]
v.scan(/([^\|]+)([\|,])([^\|]+)/).map {|p|p p; "#{k} IN (#{p.first}, #{p.last})"}
when v[/\-/]
v.scan(/([^-]+)([\-])([^-]+)/).map {|p|p p; "#{k} BETWEEN #{p.first} and #{p.last}"}
when v[/[<>=]/]
v.scan(/(<=?|>=?|=)([^<>=]+)/).map { |part| p part; "#{k} #{part.first} #{part.last}"}
else
"#{k} = #{v}"
end
end
def date_selector(k, v)
eurodate = /^(\d{1,2})[-\/](\d{1,2})[-\/](\d{1,4})$/
case
when v[/\|/]
v.scan(/([^\|]+)([\|])([^\|]+)/).map {|p|p p; "#{k} IN (DATE('#{p.first.gsub(eurodate,'\3-\2-\1')}'), DATE('#{p.last.gsub(eurodate,'\3-\2-\1')}'))"}
when v[/\-/]
v.scan(/([^-]+)([\-])([^-]+)/).map {|p|p p; "#{k} BETWEEN DATE('#{p.first.gsub(eurodate,'\3-\2-\1')}')' and DATE('#{p.last.gsub(eurodate,'\3-\2-\1')}')"}
when v[/<|>|=/]
parts = v.scan(/(<=?|>=?|=)(\d{1,2}[\/-]\d{1,2}[\/-]\d{2,4})/)
selection = parts.map do |part|
operator = part.first ||= "="
date = Date.parse(part.last.gsub(eurodate,'\3-\2-\1'))
"#{k} #{operator} DATE('#{date}')"
end
when v[/^(\d{1,2})[-\/](\d{1,4})$/]
"#{k} >= DATE('#{$2}-#{$1}-01') and #{k} <= DATE('#{$2}-#{$1}-31')"
else
date = Date.parse(v.gsub(eurodate,'\3-\2-\1'))
"#{k} = DATE('#{date}')"
end
end
答案 2 :(得分:3)
最简单的情况是从字符串中提取数组:
and_array = "jon AND gmail".split("AND").map{|e| e.strip}
# ["jon", "gmail"]
or_array = "jon OR sarah".split("OR").map{|e| e.strip}
# ["jon", "sarah"]
然后你可以构造一个查询字符串:
query_string = ""
and_array.each {|e| query_string += "%e%"}
# "%jon%%gmail%"
然后您使用ilike
或like
查询来获取结果:
Model.where("column ILIKE ?", query_string)
# SELECT * FROM model WHERE column ILIKE '%jon%%gmail%'
# Results: jonsmith@gmail.com
当然,这可能有点矫枉过正。但这是一个简单的解决方案。