我正在尝试在JAVA中创建一个SNMP客户端。
SNMPManager client = new SNMPManager("udp:73.251.102.191/162");
这对ipv4地址有好处,但是当我尝试对ipv6地址执行相同操作时,会抛出以下错误。
错误:
---------------Exception in thread "main" org.snmp4j.MessageException: No route to host
at org.snmp4j.MessageDispatcherImpl.sendPdu(Unknown Source)
at org.snmp4j.Snmp.sendMessage(Unknown Source)
at org.snmp4j.Snmp.send(Unknown Source)
at org.snmp4j.Snmp.send(Unknown Source)
at snmpTrial1.SNMPManager.get(SNMPManager.java:55)
at snmpTrial1.SNMPManager.getAsString(SNMPManager.java:45)
at snmpTrial1.SNMPManager.main(SNMPManager.java:34)
代码:此代码适用于ipv4地址,但不适用于ipv6
public class SNMPManager {
Snmp snmp = null;
String address = null;
public SNMPManager(String add)
{
address = add;
}
public static void main(String[] args) throws IOException {
SNMPManager client = new SNMPManager("udp:XXXX:XXXX:XXXX:XXXX:XXXX:XXXX:XXXX:XXXX/162"); // ipv6 address
client.start();
String sysDescr = client.getAsString(new OID(".1.3.6.1.4.1.4115.1.20.1.1.3.62.4.1.1.1"));
System.out.println(sysDescr);
}
private void start() throws IOException {
TransportMapping transport = new DefaultUdpTransportMapping();
snmp = new Snmp(transport);
transport.listen();
}
public String getAsString(OID oid) throws IOException {
ResponseEvent event = get(new OID[] { oid });
return event.getResponse().get(0).getVariable().toString();
}
public ResponseEvent get(OID oids[]) throws IOException {
PDU pdu = new PDU();
for (OID oid : oids) {
pdu.add(new VariableBinding(oid));
}
pdu.setType(PDU.GET);
ResponseEvent event = snmp.send(pdu, getTarget(), null);
if(event != null) {
return event;
}
throw new RuntimeException("GET timed out");
}
private Target getTarget() {
Address targetAddress = GenericAddress.parse(address);
CommunityTarget target = new CommunityTarget();
target.setCommunity(new OctetString("xxxxx"));
target.setAddress(targetAddress);
target.setRetries(2);
target.setTimeout(2000);
target.setVersion(SnmpConstants.version2c);
return target;
}
}
答案 0 :(得分:0)
如果您的操作系统是MAC OSX,则Java 7和8存在与IPv6和套接字连接相关的错误。这里是链接:jvm bug Java 6似乎工作正常。
答案 1 :(得分:0)
我找到了解决方案。 对于ipv6地址,我们应该具有如下格式 GenericAddress.parse(" UDP:[XXXX:XXXX:XXXX:XXXX:XXXX:XXXX:XXXX:XXXX] / 162&#34);
这对我有用。