SQL Pivot只有两个列

时间:2015-07-13 08:34:38

标签: sql sql-server tsql pivot

我正在尝试在包含两行的表上执行PIVOT:

Category       |   Sector
---------------------------
Bulbs          |   DIY
Bulbs          |   Home
Picnic blanket |   DIY
Picnic blanket |   Home
Picnic blanket |   Interior

每个类别可以有1个或更多个扇区。

我正试图找到这样一张桌子:

Category       | Sector 1  | Sector 2  | Sector 3
-------------------------------------------------
Bulbs          | DIY       | Home      | NULL
Picnic blanket | DIY       | Home      | Interior

查询如下所示:

SELECT
    dbo.fn_DbContent_GetTranslation(pt.Name_DbContentId, 2) 'Category'
    , dbo.fn_DbContent_GetTranslation(s.Name_DbContentId, 2) 'Sector'
FROM dbo.ProductType pt
JOIN dbo.ProductTypeMandator ptm ON ptm.ProductTypeId = pt.Id
JOIN dbo.ProductTypeMandator2PortalSector ptmps ON ptmps.ProductTypeMandatorId = ptm.Id
JOIN dbo.PortalSector ps ON ps.Id = ptmps.PortalSectorId
JOIN dbo.Sector s ON s.Id = ps.SectorId
WHERE
    ptmps.PortalSectorId IN (21, 18, 19)

我已经做了一个PIVOT但是有一个包含三列的表,其中一列包含数据透视表中标题的值。在这种情况下,标题的值丢失了,所以我不知道如何做。

感谢您的帮助

2 个答案:

答案 0 :(得分:2)

你可以这样解决:

-- Create demo data
CREATE TABLE #cats(category nvarchar(25), sector nvarchar(25))

INSERT INTO #cats(category, sector)
VALUES  (N'Bulbs',N'DIY'),
        (N'Bulbs',N'Home'),
        (N'Picnic blanket',N'DIY'),
        (N'Picnic blanket',N'Home'),
        (N'Picnic blanket',N'Interior')

SELECT *
FROM (
    SELECT category, sector
    FROM #cats
) as dat
PIVOT(
    MAX(sector)
    FOR sector IN([DIY],[Home],[Interior])
) as pvt

-- Cleanup
DROP TABLE #cats

如果您希望在示例中正确命名它,可以将其与命名编号结合使用:

-- Create demo data
CREATE TABLE #cats(category nvarchar(25), sector nvarchar(25))

INSERT INTO #cats(category, sector)
VALUES  (N'Bulbs',N'DIY'),
        (N'Bulbs',N'Home'),
        (N'Picnic blanket',N'DIY'),
        (N'Picnic blanket',N'Home'),
        (N'Picnic blanket',N'Interior')

SELECT *
FROM (
    SELECT category, sector, N'Sector '+CONVERT(nvarchar(max),DENSE_RANK() OVER(ORDER BY sector)) as rn
    FROM #cats
) as dat
PIVOT(
    MAX(sector)
    FOR rn IN([Sector 1],[Sector 2],[Sector 3])
) as pvt

-- Cleanup
DROP TABLE #cats

最后但并非最不重要的,如果你想要它是动态的:

-- Create demo data
CREATE TABLE #cats(category nvarchar(25), sector nvarchar(25))

INSERT INTO #cats(category, sector)
VALUES  (N'Bulbs',N'DIY'),
        (N'Bulbs',N'Home'),
        (N'Picnic blanket',N'DIY'),
        (N'Picnic blanket',N'Home'),
        (N'Picnic blanket',N'Interior')

DECLARE @sql nvarchar(max), @cols nvarchar(max)

-- get proper column list
SELECT @cols = COALESCE(@cols + N',[' + grCols.rn + N']',N'[' + grCols.rn + N']')
FROM (
    SELECT DISTINCT N'Sector '+CONVERT(nvarchar(max),DENSE_RANK() OVER(ORDER BY sector)) as rn
    FROM #cats
) as grCols

SET @sql = N'
SELECT *
FROM (
    SELECT category, sector, N''Sector ''+CONVERT(nvarchar(max),DENSE_RANK() OVER(ORDER BY sector)) as rn
    FROM #cats
) as dat
PIVOT(
    MAX(sector)
    FOR rn IN('+@cols+')
) as pvt'
EXEC(@sql)

-- Cleanup
DROP TABLE #cats

答案 1 :(得分:0)

你可以用两种方式做到这一点,

一个是Conditional Aggregate

;WITH cte
     AS (SELECT *,
                rn=Row_number()
                     OVER(
                       partition BY category
                       ORDER BY (SELECT NULL))
         FROM   yourtable)
SELECT category,
       [sector 1] = Max(CASE WHEN rn = 1 THEN sector END),
       [sector 2] = Max(CASE WHEN rn = 2 THEN sector END),
       [sector 3] = Max(CASE WHEN rn = 3 THEN sector END)
FROM   cte
GROUP  BY category

另一种方法是使用Pivot

SELECT *
FROM   (SELECT *,
               sector_col = 'sector '
                            + Cast(Row_number()OVER(partition BY category ORDER BY (SELECT NULL)) AS VARCHAR(20))
        FROM   yourtable) A
       PIVOT (Max(sector)
             FOR sector_col IN ([sector 1],
                                [sector 2],
                                [sector 3])) piv 

注意:正如评论中所述,如果sector值不是staticunknown,那么您可以将其转换为dynamic query