我在java中有一个程序,要求用户输入10个整数,并打印出ODD的数量和EVEN的数量。
import java.io.*;
public class Count {
public static void main(String[] args) {
int i, , even_ctr=0, odd_ctr = 0;
String input = " ";
BufferedReader in = new BufferedReader ( new InputStreamReader(System.in));
for(i = 1; i <=10; i++){
try{
System.out.print("Input integer number: ");
input = in.readLine();
}catch(IOException e){
System.out.println("Error!");
}
n = Integer.parseInt(input);
if(n % 2 == 0)
even_ctr++; //counter for even
if(n % 2 == 0)
odd_ctr++; //counter for odd
}System.out.println("EVEN: " + even_ctr + "\nODD: "+ odd_ctr);
}
}
我试图通过仅使用一个计数器而不是两个计数器来更改程序。谁知道怎么做?
答案 0 :(得分:0)
import java.io.*;
public class NewClass {
public static void main(String[] args) {
int i,n, even_ctr=0;
String input = " ";
BufferedReader in = new BufferedReader ( new InputStreamReader(System.in));
for(i = 1; i <=10; i++){
try{
System.out.print("Input integer number: ");
input = in.readLine();
}catch(IOException e){
System.out.println("Error!");
}
n = Integer.parseInt(input);
if(n % 2 == 0)
even_ctr++;
}System.out.println("EVEN: " + even_ctr + "\nODD: "+ (10-even_ctr));
}
}
答案 1 :(得分:0)
保持第一个计数器递增以进行ODD编号检测(或者偶然但是其中任何一个)。在计算结束时,如果ODD计数器= 4,输入的总数是10,那么10 - ODDcounter = 10 - 4 = 6是偶数的数量。
答案 2 :(得分:0)
为此,看起来使用扫描仪同样有用,这样就可以避免必须解析字符串的步骤。这也需要你import java.util.Scanner
,但你可以使用扫描仪来在字符串或整数。
Scanner in = new Scanner(System.in);
int input;
int evenCount = 0;
for(i = 1; i <=10; i++){
try{
System.out.print("Input integer number: ");
input = in.nextInt();
}catch(IOException e){
System.out.println("Error!");
}
if(input % 2 == 0)
evenCount++;
}
System.out.println("EVEN: " + evenCounter + "\nODD: "+ (10 - evenCounter);
在方法结束时包含in.close();
以关闭扫描仪或您使用的阅读器。
答案 3 :(得分:-1)
package evenoddten;
import java.util.Scanner;
public class EvenOddTen {
public static void main(String[] args) {
int num1 = 0, num2, even = 0, count = 0;
Scanner scr = new Scanner(System.in);
System.out.print("Total Nos:");
num2 = scr.nextInt();
while(count<num2) {
System.out.println("Enter no:");
num1 = scr.nextInt();
if (num1%2 == 0) {
even = even + 1;
}
count = count+1;
}
System.out.println("Even nos are:"+even);
System.out.println("Odd nos are:"+(count - even));
}
}