Question

我有一个字符串和一张地图，如下所述：

我想使用地图中存在的值替换花括号中的值（如果地图中存在相应的键，则保持相同）。

void main()
{
    Stack *S = new Stack;
    char val;

    while(true)
    {
        cout<<"enter character:"<<endl;
        cin>>val;
        S->push(val);
    }

    S->pop();
}

我希望输出为字符串，应该是：

String input = "[text{100}any text1({200})text2{300}{400}{500}not{600}]";
Map<String,String> map = new HashMap<>();
map.put("{100}", "hundred");
map.put("{200}", "two hundred");
map.put("{300}", "three hundred");
map.put("{400}", "four hundred");
map.put("{500}", "five hundred");

我的代码是：

"[text hundred any text1 (two hundred) text2 three hundred,four hundred,five hundred not{600}]"

我的输出：

String uuidString = "[text{100}any text1({200})text2{300}{400}{500}not{600}]";

Map<String,String> map = new HashMap<>();
map.put("{100}", "hundred");
map.put("{200}", "two hundred");
map.put("{300}", "three hundred");
map.put("{400}", "four hundred");
map.put("{500}", "five hundred");

String[] uuidList = uuidString.split("(?=\\{)|(?<=\\})");
String uuidValue;


for(int i=0;i<uuidList.length;i++){
    uuidValue = map.get(uuidList[i]);
    if(uuidValue != null){
        uuidList[i]=uuidValue;
    }
}
uuidString = Arrays.toString(uuidList);
System.out.println("string :"+uuidString);

我只需要连续大括号的逗号，并希望我的输出如下：

string :[[text, hundred, any text1(, two hundred, )text2, three hundred, four hundred, five hundred, not, {600}, ]] but

Answer 1

只需与

匹配

\{\d+?\}

在哈希中找到相应的值，并将上面的匹配替换为找到的值。

String uuidString = "[text{100}any text1({200})text2{300}{400}{500}not{600}]";

Map<String,String> map = new HashMap<>();
map.put("{100}", "hundred");
map.put("{200}", "two hundred");
map.put("{300}", "three hundred");
map.put("{400}", "four hundred");
map.put("{500}", "five hundred");

Pattern numberInCurlyBrackets = Pattern.compile("\\{\\d+?\\}");
Matcher matcher = numberInCurlyBrackets.matcher(uuidString);

while(matcher.find()) {
    String replacee = matcher.group();
    String replacement = map.get(replacee);
    if (replacement != null)
        uuidString = uuidString.replace(replacee, replacement);
}
System.out.println(uuidString);

通过修改hashmap中存在的名称值来替换字符串中的id值

1 个答案: