Question

我想写一个JavaScript函数，它找出最大和最小数字之间的差异。输入可以是任何数字，因此我使用<?php class A { static $foo = 42; static $baz = 4; } class B extends A { static $bar = 2; static $baz = 44; } function isOwnStaticProperty($class, $prop) { $reflect = new ReflectionClass($class); //Filtering only the statics values with ReflectionProperty::IS_STATIC $props = $reflect->getProperties(ReflectionProperty::IS_STATIC); foreach ($props as $object) { if($object->class == $class && $object->name == $prop) { return true; } } return false; } $class_name = 'A'; echo isOwnStaticProperty($class_name, 'foo') ? "TRUE \n" : "FALSE \n"; $class_name = 'B'; echo isOwnStaticProperty($class_name, 'foo') ? "TRUE \n" : "FALSE \n"; $class_name = 'B'; echo isOwnStaticProperty($class_name, 'bar') ? "TRUE \n" : "FALSE \n"; $class_name = 'A'; echo isOwnStaticProperty($class_name, 'bar') ? "TRUE \n" : "FALSE \n"; $class_name = 'B'; echo isOwnStaticProperty($class_name, 'baz') ? "TRUE \n" : "FALSE \n"; $class_name = 'A'; echo isOwnStaticProperty($class_name, 'baz') ? "TRUE \n" : "FALSE \n";。

我写了一个最大和最小功能，单独他们工作正常。我把它们放在差值函数中来计算max-min并返回结果。但是某处有一个错误，代码没有按预期运行。

arguments

Answer 1

试试这个

var Doctor = bookshelf.Model.extend({

  tableName: "d_doctor",
  idAttribute: "d_doctorid",

  patients: function() {
    return this.belongsToMany(Patient).through(Appointment,"a_d_doctorid","a_p_patientid");
  }

});

var Appointment = bookshelf.Model.extend({

  tableName : "a_appointment",
  idAttribute : "a_appointmentid",

  patient: function() {
    return this.belongsTo(Patient,"a_p_patientid");
  },

  doctor: function() {
    return this.belongsTo(Doctor,"a_d_doctorid");
  }

});

var Patient = bookshelf.Model.extend({

  tableName : "p_patient",
  idAttribute : "p_patientid",

  doctors: function() {
    return this.belongsToMany(Doctor).through(Appointment,"a_p_patientid", "a_d_doctorid");
  }

});

无需无限

Answer 2

您从不致电findMin()或findMax()。

您可以使用内置Math.min()或Math.max()，它们都可以使用无限数量的参数，因此您可以避免自己迭代参数。

像这样：

function difference() {
    var min = Math.min.apply(null, arguments),
        max = Math.max.apply(null, arguments);

    return max - min;
}

Answer 3

你可以在一个for循环中更轻松地完成它：

var numbers = [4, 8, 1, 100, 50];

function difference(arr) {
    var max = arr[0]
    var min = arr[0];
    for(var i = 0; i < arr.length; i += 1) {
        if(arr[i] > max) {
            max = arr[i];
        }
        if(arr[i] < min) {
            min = arr[i];
        }
    }
    var d = max - min;
    return d;
}

var result = difference(numbers);
console.log(result);

Answer 4

如果由于某种原因您希望使用现有的findMin()和findMax()方法，那么您只是错过了对这些方法的调用。

在difference()内，你应该这样做：

var numbers = Array.slice(arguments);   // create an array of args
var max = findMax.apply(this, numbers);
var min = findMin.apply(this, numbers);
return max - min;

如果您希望处理负数，请按照评论的建议修复您的findMax()方法。

Javascript任何数字的差异

4 个答案: