Question

我正在尝试使用bind_result和while-fetch将一组数据提取到二维数组中，我已经在互联网上搜索了解决方案，但它没有按预期工作。经过几个小时的调试后，我不确定代码中出了什么问题。感谢是否有人可以帮助检测盲点。

情景：

我有一张表格如下：

tbl_team
teamname    id      name    gender
team1       1       John    Male
team1       2       Kelly   Female
team1       3       Chan    Male
team2       1       Jordan  Male
... etc

我创建了一个基于teamname查询这些函数的函数。

<?php 
function queryteam ($team)
{
  $stmt = $mysqli->prepare("select id, name, gender from tbl_team where teamname = ?");
   if($stmt)
  {
     $stmt->bind_param('s',$team);
     $stmt->execute();
     $stmt->store_result();
     $stmt->bind_result($team_member['id'],$team_member['name'],$team_member['gender']);
     $team = array();
     while($stmt->fetch())
     {
       //echo implode(" - ", $team_member)."<br>"; //debug purpose
       $team[] = $team_member;
     }
     $stmt->close();
     return $team;
  }
}
?>

然后我有一部分代码将调用此函数并在屏幕上打印结果：

<?php
  $team_array = queryteam( "team1");
  FOR($i = 0, $count=count($team_array);$i<$count;$i++)
  {
     echo "Team1 Members as below:<br>";
     echo implode(" - ",$team_array[$i])."<br>";
  }
?>

预期结果如下：

Team1 Members as below:
1 - John - Male
2 - Kelly - Female
3 - Chan - Male

但实际上我得到的结果如下：

Team1 Members as below:
3 - Chan - Male
3 - Chan - Male
3 - Chan - Male

查询返回结果是正确的，因为我试图在while（fetch）期间回显，但问题是，在while内部，数组被最新的获取结果覆盖。

提前感谢所有帮助。

**编辑我编辑了脚本，并按照Geo的评论进行了测试：

<?php 
  function queryteam ($team)
  {
    ....
       $team = array();
       while($stmt->fetch())
       {
         //echo implode(" - ", $team_member)."<br>"; //debug purpose
         $team[] = $team_member;
         echo "within FETCH: <br>";
         print_r($team); echo "<br>";
       }
       $stmt->close();
       return $team;
    }
  }
  $team_array = queryteam( "team1");
  echo "Function returned:<br>";
  print_r($team_array); echo "<br>";
  ?>

我得到的结果如下：

within FETCH:
Array([0]=>Array([id]=>1 [name]=>John [gender]=>Male))
Array([0]=>Array([id]=>2 [name]=>Kelly [gender]=>Female) [1]=>Array([id]=>2 [name]=>Kelly [gender]=>Female))
Array([0]=>Array([id]=>3 [name]=>Chan [gender]=>Male) [1]=>Array([id]=>3 [name]=>Chan [gender]=>Male) [2]=>Array([id]=>3 [name]=>Chan [gender]=>Male))
Function returned:
Array([0]=>Array([id]=>3 [name]=>Chan [gender]=>Male) [1]=>Array([id]=>3 [name]=>Chan [gender]=>Male) [2]=>Array([id]=>3 [name]=>Chan [gender]=>Male))
Array([0]=>Array([id]=>3 [name]=>Chan [gender]=>Male) [1]=>Array([id]=>3 [name]=>Chan [gender]=>Male) [2]=>Array([id]=>3 [name]=>Chan [gender]=>Male))
Array([0]=>Array([id]=>3 [name]=>Chan [gender]=>Male) [1]=>Array([id]=>3 [name]=>Chan [gender]=>Male) [2]=>Array([id]=>3 [name]=>Chan [gender]=>Male))

Answer 1

感谢Orangepill和evans_murithi！

我从没想过它是由bind_result引起的

修改如下：

<?php 
function queryteam ($team)
{
  $stmt = $mysqli->prepare("select id, name, gender from tbl_team where teamname = ?");
   if($stmt)
  {
     $stmt->bind_param('s',$team);
     $stmt->execute();
     $stmt->store_result();

     //change this part
     //$stmt->bind_result($team_member['id'],$team_member['name'],$team_member['gender']);
     $stmt->bind_result($id, $name, $gender);
     /*******/

     $team = array();
     while($stmt->fetch())
     {
       $team_member = array();
       $team_member['id'] = $id;
       $team_member['name'] = $name;
       $team_member['gender'] = $gender;
       //echo implode(" - ", $team_member)."<br>"; //debug purpose
       $team[] = $team_member;
     }
     $stmt->close();
     return $team;
  }
}
?>

PHP获取到多维数组

1 个答案: