Question

我有一个表和一列包含id号码+数字+字母。我知道如何分离并创建另一个（新）列，但我想按新列分组：

 SELECT  A.COLUMN1 ,
         B.COLUMN1,  
        (LEFT(SUBSTRING(B.COLUMN1, PATINDEX('%[0-9.-]%', B.COLUMN1), 10),
               PATINDEX('%[^0-9.-]%', SUBSTRING(B.COLUMN1, PATINDEX('%[0-9.-]%', B.COLUMN1), 10) + 'X') -1)) as name2

    FROM    TABLE_B AS B           
            LEFT OUTER JOIN TABLE_A AS A ON B.COLUMN123 = A.COLUMN123

    WHERE   A.COLUMN1='VALUE'
GROUP BY B.COLUMN1,  A.COLUMN1

所以我的报告如下：

    name1   name2  name2
    VALUE1  1      1
    VALUE   2      2
    VALUE3  3      1
    VALUE   4      4
    VALUE   27xz   27
   VALUE    27zx    27

如何按名称2分组？

Answer 1

最简单的方法是使用CTE或子查询：

 WITH cte as (
       SELECT A.COLUMN1, B.COLUMN1,  
              (LEFT(SUBSTRING(B.COLUMN1, PATINDEX('%[0-9.-]%', B.COLUMN1), 10),
               PATINDEX('%[^0-9.-]%', SUBSTRING(B.COLUMN1, PATINDEX('%[0-9.-]%', B.COLUMN1), 10) + 'X') -1)) as new_column
       FROM TABLE_B B LEFT OUTER JOIN
            TABLE_A A
            ON B.COLUMN123 = A.COLUMN123
       WHERE A.COLUMN1 = 'VALUE'
      )
SELECT new_column, COUNT(*)
FROM cte
GROUP BY new_column;

SQL group by子查询

1 个答案: