如何编写语言纤细的嵌套标签

时间:2015-07-08 08:12:18

标签: ruby slim-lang

我想在下面用语言写作。

<li class="active"><a href="#">Link <span class="sr-only">(current)</span></a></li>  

<a href="#" class="dropdown-toggle" data-toggle="dropdown" role="button" aria-haspopup="true" aria-expanded="false">Dropdown <span class="caret"></span></a>  

我可以通过内联HTML嵌入它,所以很有趣。

2 个答案:

答案 0 :(得分:1)

li.active
  a href="#"
    ' Link
    span.sr-only
      | (current)

a.dropdown-toggle href="#" data-toggle="dropdown" role="button" aria-haspopup="true" aria-expanded="false"
  ' Dropdown
  span.caret

答案 1 :(得分:1)

HTML:

<li class="active"><a href="#">Link <span class="sr-only">(current)</span></a></li>

SLIM:

li.active
  a href="#" 
    | Link
    span.sr-only (current)

以及此HTML代码:

<a href="#" class="dropdown-toggle" data-toggle="dropdown" role="button" aria-haspopup="true" aria-expanded="false">Dropdown <span class="caret"></span></a>  

你可以写苗条:

a.dropdown-toggle aria-expanded="false" aria-haspopup="true" data-toggle="dropdown" href="#" role="button" 
  | Dropdown
  span.caret

供您参考: