我正在尝试使用LEFT JOIN替换NOT IN但由于某种原因无法获得所需的结果。
这是原始查询
def generate_population(N, genomelength):
x = []
for i in range(N):
i = gen_individual(genomelength)
x.append(i)
原始代码(这应该给'2'):
create table #versions
(
Ruleid int, IsDraft INT
)
-- prod #versions
insert into #versions values (1, 0)
insert into #versions values (2, 0) -- this will be deleted
-- Draft version
insert into #versions values (1, 1) -- changed added
更改代码:
-- Getting all the rules that are deleted
select distinct vp.ruleid from #versions vp where vp.IsDraft = 0
except
select distinct vd.ruleid from #versions vd where vd.IsDraft = 1
我错过了什么...... ???
请指教。
感谢。
答案 0 :(得分:4)
不确定为什么要LEFT JOIN
。我认为NOT EXISTS
在这种情况下更合适,假设我明白你要做什么。您实际上并未指定所需的结果,因此我假设您要重现先前查询的结果。
SELECT DISTINCT vp.RuleId
FROM #versions vp
WHERE vp.IsDraft = 0
AND NOT EXISTS (
SELECT null
FROM #versions vd
WHERE vd.RuleId = vp.RuleId
AND vd.IsDraft = 1
)
答案 1 :(得分:1)
如果你真的想和ANTI -JOIN一起使用,你需要做两件事
1)测试连接的右侧以查看值是否为空
2)不要在联接的左侧包含过滤器
SELECT vp.ruleid
FROM #versions vp
LEFT JOIN #versions vd
ON vd.ruleid = vp.ruleid
AND vd.isdraft = 1
WHERE vp.isdraft = 0
AND vd.ruleid IS NULL