Question

我有这个查询

WITH summary AS 
(
   SELECT  Msisdn, DateRegistered , 
       RANK() OVER  (ORDER BY DateRegistered ASC) AS dRank 
   FROM dbo.SubscriptionsArchive 
   WHERE MSISDN='123456'
)
SELECT s.msisdn, s.DateRegistered AS firstReg 
FROM summary s 
WHERE dRank =(SELECT max(dRank) FROM summary )

这显示对应于min Rank的firstReg，我想同时获得与maxRank对应的lastReg。我如何实现这一目标？

Answer 1

使用TOP 1语法交叉连接CTE的第一行和最后一行的解决方案：

WITH summary AS 
(
   SELECT  Msisdn, DateRegistered , 
       RANK() OVER  (ORDER BY DateRegistered ASC) AS dRank 
   FROM dbo.SubscriptionsArchive 
   WHERE MSISDN='123456'
)
SELECT minrow.*, maxrow.*
FROM 
   (select TOP 1 * from summary order by dRank desc) minrow
   CROSS JOIN
   (select TOP 1 * from summary order by dRank asc) maxrow ;

Answer 2

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在ms sql中获取列的最大值，对应于列的最小值的最小值

2 个答案: