我使用mp4parser来合并音频和视频文件,下面是我尝试过的示例,但我在第一行本身得到空指针异常。我已将音频和视频文件保存在手机内存中的所需位置。如果我调试,第一行需要大量的时间和时间只需在空指针错误后停止
try
{
H264TrackImpl h264Track = new H264TrackImpl(new FileDataSourceImpl("/mnt/sdcard/myvideo/video.mp4"));
AACTrackImpl aacTrack = new AACTrackImpl(new FileDataSourceImpl("/mnt/sdcard/myvideo/audio.acc"));
Movie movie = new Movie();
movie.addTrack(h264Track);
movie.addTrack(aacTrack);
Container mp4file = new DefaultMp4Builder().build(movie);
FileChannel fc = new FileOutputStream(new File("output.mp4")).getChannel();
mp4file.writeContainer(fc);
fc.close();
} catch (Exception ee)
{
Toast.makeText(this,ee.getMessage(),Toast.LENGTH_LONG).show();
}
我的上述代码有什么不对?
答案 0 :(得分:1)
**试试这个 我已经遵循了很少的东西来合并音频和视频。
5)按钮点击或On Crete
调用方法String audiopath =“/ sdcard / audio.m4a”;
String videopath =“/ sdcard / video.mp4”;
String outputpath =“/ sdcard / output.mp4”;
mux(视频,音频,输出);
6)主代码在这里仅传递存储视频,音频(m4a,aac),输出路径的路径。
public boolean mux(String videoFile, String audioFile, String outputFile) {
Movie video;
try {
video = new MovieCreator().build(videoFile);
} catch (RuntimeException e) {
e.printStackTrace();
return false;
} catch (IOException e) {
e.printStackTrace();
return false;
}
Movie audio;
try {
audio = new MovieCreator().build(audioFile);
} catch (IOException e) {
e.printStackTrace();
return false;
} catch (NullPointerException e) {
e.printStackTrace();
return false;
}
Track audioTrack = audio.getTracks().get(0);
video.addTrack(audioTrack);
Container out = new DefaultMp4Builder().build(video);
FileOutputStream fos;
try {
fos = new FileOutputStream(outputFile);
} catch (FileNotFoundException e) {
e.printStackTrace();
return false;
}
BufferedWritableFileByteChannel byteBufferByteChannel = new BufferedWritableFileByteChannel(fos);
try {
out.writeContainer(byteBufferByteChannel);
byteBufferByteChannel.close();
Log.e("Audio Video", "11");
fos.close();
} catch (IOException e) {
e.printStackTrace();
return false;
}
return true;
}
private static class BufferedWritableFileByteChannel implements WritableByteChannel {
// private static final int BUFFER_CAPACITY = 1000000;
private static final int BUFFER_CAPACITY = 10000000;
private boolean isOpen = true;
private final OutputStream outputStream;
private final ByteBuffer byteBuffer;
private final byte[] rawBuffer = new byte[BUFFER_CAPACITY];
private BufferedWritableFileByteChannel(OutputStream outputStream) {
this.outputStream = outputStream;
this.byteBuffer = ByteBuffer.wrap(rawBuffer);
Log.e("Audio Video", "13");
}
@Override
public int write(ByteBuffer inputBuffer) throws IOException {
int inputBytes = inputBuffer.remaining();
if (inputBytes > byteBuffer.remaining()) {
Log.e("Size ok ", "song size is ok");
dumpToFile();
byteBuffer.clear();
if (inputBytes > byteBuffer.remaining()) {
Log.e("Size ok ", "song size is not okssss ok");
throw new BufferOverflowException();
}
}
byteBuffer.put(inputBuffer);
return inputBytes;
}
@Override
public boolean isOpen() {
return isOpen;
}
@Override
public void close() throws IOException {
dumpToFile();
isOpen = false;
}
private void dumpToFile() {
try {
outputStream.write(rawBuffer, 0, byteBuffer.position());
} catch (IOException e) {
throw new RuntimeException(e);
}
}
}