C版:
require 'open-uri'
def http_download(uri, filename)
bytes_total = nil
index = 1
begin
open(
uri,
read_timeout: 500,
content_length_proc: lambda { |content_length|
bytes_total = content_length
},
progress_proc: lambda { |bytes_transferred|
if bytes_total
print("\r#{bytes_transferred} of #{bytes_total} bytes")
else
print("\r#{bytes_transferred} bytes (total size unknown)")
end
}
) do |io|
# if "application/json" == io.content_type
if io.is_a? StringIO
raise " --> Failed, server is processing. Retry the request ##{index}"
else # Tempfile
puts "\n--> Succeed, writing to #{filename}"
File.open(filename, 'w'){|wf| wf.write io.read}
end
end
rescue => e
puts e
return if e.is_a? OpenURI::HTTPError # Processing error
index += 1
return if index > 10
sleep index and retry
end
end
结果:
#include <stdio.h>
#include <stdlib.h>
unsigned int test(unsigned int n_count) {
unsigned int c = 1;
unsigned int i;
for (i=0; i< n_count;i++) {
c += 2 * 34 + 1;
c /= 2;
c *= 39;
}
return c;
}
int main(int argc, char* argv[])
{
printf("%u\n", test(atoi(argv[1])));
}
erlang版本:
$ gcc p2.c
$ time ./a.out 100000000
563970997
real 0m0.865s
user 0m0.864s
sys 0m0.004s
结果:
-module(test2).
-export([main/1]).
-mode(compile).
calc(Cnt, Total) when Cnt > 0 ->
if Total >= 4294967296 -> Total2 = Total rem 4294967296;
true -> Total2 = Total end,
calc(Cnt - 1, trunc((Total2 + 2 * 34 + 1) / 2) * 39);
calc(0, Total)->
if Total >= 4294967296 -> Total2 = Total rem 4294967296;
true -> Total2 = Total end,
io:format("~p ~n", [Total2]),
ok.
main([A])->
Cnt = list_to_integer(A),
calc(Cnt, 1).
如何提高erlang版本的性能? 在erlang中,我必须模拟整数溢出的情况,有更好的方法吗? 即使使用hipe,性能也远不是C。
修改
Python版本:
$ erlc +native +"{hipe, [to_llvm]}" test2.erl
$ time escript test2.beam 100000000
563970997
real 0m4.940s
user 0m4.892s
sys 0m0.056s
$ erlc +native test2.erl
$ time escript test2.beam 100000000
563970997
real 0m5.381s
user 0m5.320s
sys 0m0.064s
$ erlc test2.erl
$ time escript test2.beam 100000000
563970997
real 0m9.868s
user 0m9.808s
sys 0m0.056s
结果:
def test(n_count):
c = 1
for i in xrange(n_count):
c += 2 * 34 + 1
c /= 2
c *= 39
if c >= 4294967296:
c = c % 4294967296
return c
print test(100000000)
答案 0 :(得分:1)
我认为以下链接可能特别有用,您将能够“烘焙”#39;你的C代码进入你的Erlang应用程序:
答案 1 :(得分:0)
Erlang在数字滚动任务方面确实不太好。很好,如果你想要占用字节并发送它们。
当您将一些瓶颈模块重写为本机时,通常严重的Erlang开发周期包括最终优化。
是的,Erlang看起来像是好的计算(和像Wings3D这样的项目显示),但也许你必须选择其他工具?