表单模板来源:http://www.html-form-guide.com/contact-form/php-email-contact-form.html
HTML表单页:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>Contact us</title>
<!-- define some style elements-->
<style>
h1
{
font-family : Arial, Helvetica, sans-serif;
font-size : 16px;
font-weight : bold;
}
label,a
{
font-family : Arial, Helvetica, sans-serif;
font-size : 12px;
}
</style>
<!-- a helper script for vaidating the form-->
<script language="JavaScript" src="scripts/gen_validatorv31.js" type="text/javascript"></script>
</head>
</head>
<body>
<h1>Contact us</h1>
<form method="POST" name="contactform" action="contact-form-handler.php">
<p>
<label for='name'>Your Name:</label> <br>
<input type="text" name="name">
</p>
<p>
<label for='email'>Email Address:</label> <br>
<input type="text" name="email"> <br>
</p>
<p>
<label for='message'>Message:</label> <br>
<textarea name="message"></textarea>
</p>
<input type="submit" value="Submit"><br>
</form>
<script language="JavaScript">
// Code for validating the form
// Visit http://www.javascript-coder.com/html-form/javascript-form-validation.phtml
// for details
var frmvalidator = new Validator("contactform");
frmvalidator.addValidation("name","req","Please provide your name");
frmvalidator.addValidation("email","req","Please provide your email");
frmvalidator.addValidation("email","email","Please enter a valid email address");
</script>
<!--
Sample code from:
http://www.html-form-guide.com/contact-form/php-email-contact-form.html
-->
</body>
</html>
PHP脚本:
<?php
$errors = '';
$myemail = 'yourname@website.com';//<-----Put Your email address here.
if(empty($_POST['name']) ||
empty($_POST['email']) ||
empty($_POST['message']))
{
$errors .= "\n Error: all fields are required";
}
$name = $_POST['name'];
$email_address = $_POST['email'];
$message = $_POST['message'];
if (!preg_match(
"/^[_a-z0-9-]+(\.[_a-z0-9-]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,3})$/i",
$email_address))
{
$errors .= "\n Error: Invalid email address";
}
if( empty($errors))
{
$to = $myemail;
$email_subject = "Contact form submission: $name";
$email_body = "You have received a new message. ".
" Here are the details:\n Name: $name \n Email: $email_address \n Message \n $message";
$headers = "From: $myemail\n";
$headers .= "Reply-To: $email_address";
mail($to,$email_subject,$email_body,$headers);
//redirect to the 'thank you' page
header('Location: contact-form-thank-you.html');
}
?>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>Contact form handler</title>
</head>
<body>
<!-- This page is displayed only if there is some error -->
<?php
echo nl2br($errors);
?>
</body>
</html>
详情: 当我输入一些细节然后单击提交时,我被重定向到浏览器中的PHP脚本。我可以请一些指导,因为我已经研究了很多,并且不太了解PHP。 我希望有足够的细节!
答案 0 :(得分:0)
如果您不希望您的表单在php页面上重定向,那么您需要使用ajax提交表单然后从php文件获取响应。给你的表单一个id(假设id是contactform)
// Jquery代码
<script>
$("#contactform").submit(function(event){
event.preventDefault();
$.ajax({
method: "POST",
url: "contact-form-handler.php",
data: { name: $("#name"), email: $("#email"),message: $("#message") },
success: function(response){
alter(response.data);
}
})
})
</script>
// PHP-CODE
$errors = '';
$myemail = 'yourname@website.com';//<-----Put Your email address here.
if(empty($_POST['name']) ||
empty($_POST['email']) ||
empty($_POST['message']))
{
$errors .= "\n Error: all fields are required";
}
$name = $_POST['name'];
$email_address = $_POST['email'];
$message = $_POST['message'];
if (!preg_match(
"/^[_a-z0-9-]+(\.[_a-z0-9-]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,3})$/i",
$email_address))
{
$errors .= "\n Error: Invalid email address";
}
if( empty($errors))
{
$to = $myemail;
$email_subject = "Contact form submission: $name";
$email_body = "You have received a new message. ".
" Here are the details:\n Name: $name \n Email: $email_address \n Message \n $message";
$headers = "From: $myemail\n";
$headers .= "Reply-To: $email_address";
mail($to,$email_subject,$email_body,$headers);
//Set an success message, here i have used the variable name as error you can change it as per requirment.
$error = 'Mail Sent successfully !!';
}
$data['error'] = $error;
echo json_encode($data);
exit();