我有一个像下面这样的数据库模式 -
(Country table)
| Country | Country Code|
-------------------------
ABC A
BCD B
(组织表)
Org 1 A O1
Org 2 B O2
Org 3 A O3
(交易表)
O1 X1 Y1
O2 X2 Y2
O3 X3 Y3
我希望结果集像这样 -
| Corridor | Total Export | Total Import |
------------------------------------------
ABC-BCD X1+X2+X3 Y1+Y2+Y3
Corridor列应该是Country表中所有国家/地区的组合。
如何构建查询来实现此逻辑?感谢
答案 0 :(得分:1)
您需要做的就是运行聚合查询:
select sum(t.export) as TotalExport,
sum(t.import) as TotalImport
FROM country c inner join Organization o on c.Country_Code = o.Country_Code
inner join Transaction t on o.organization_code = t.organization_code
现在,您问:Corridor列在哪里?答案是:使用string_agg函数:
select string_agg(DISTINCT c.country, '-' ORDER BY c.country) as Corridor,
sum(t.export) as TotalExport,
sum(t.import) as TotalImport
FROM country c inner join Organization o on c.Country_Code = o.Country_Code
inner join Transaction t on o.organization_code = t.organization_code