Question

目前我正在使用SailsJS创建自己的网络应用。我使用skipper-s3将文件上传到AWS S3。这是我的代码：

req.file('uploadFile').upload({
  adapter: require('skipper-s3'),
  key: 'KEY',
  secret: 'SECRET',
  bucket: 'BUCKET',
  ACL: 'public-read'
}, function whenDone(err, filesUploaded) {
  if (err) {
    console.log(err);
    return res.negotiate(err);
  }

  var pt = {
    user: req.session.User.id,
    agency: req.param('id'),
    path: filesUploaded[0].extra.Location,
    filename: filesUploaded[0].filename
  };

  Transaction.create(pt, function TransactionCreated(err, trans){
    if(err) return next(err);

    return res.ok({
      files: filesUploaded,
      textParams: req.params.all(),
      trans: trans
    });
  })
});

所以我已经把＃＆＃39;路径＆＃39;和原始文件名＆＃39;到MongoDB。但是＆＃39;文件名＆＃39; S3中的内容已经使用＆＃39;随机名称＆＃39;进行了更改。那么，是否可以更改为原始文件名＆＃39;上传时？或自动更改为原始文件名＆＃39;当用户想下载它时？

此致 John Elmer Semaya

Answer 1

查看skipper documentation后，我找到了saveAs个选项。只需将其放在req.file('name').upload内，即可使用原始名称或其他自定义名称保存。

这是一个例子：

var newFilename = req.file('uploadFile')._files[0].stream.filename;

req.file('uploadFile').upload({
   adapter: require('skipper-s3'),
   key: 'KEY',
   secret: 'SECRET',
   bucket: 'BUCKET',
   ACL: 'public-read,
   saveAs: newFilename //this is how you put custom name when upload file
},
   ...
});

Answer 2

您可以设置s3params的关键参数。

const options = {
  adapter: require('skipper-s3'),
  key: 'KEY',
  secret: 'SECRET',
  bucket: 'BUCKET',
  s3params: {Key: 'full/path/to/file.jpg'} //no leading slash prevents empty folder
}

const adapter = require('skipper-better-s3')(options),
      receiver = adapter.receive();

req.file('uploadFile').upload(receiver, function(err,filesUploaded){
  //do something...
})

//More useful below

const fs = require('fs');
const file = fs.createReadStream('/tmp/my-file.jpg');

receiver.write(file, () => { 
  console.log(file.extra);
});

如何在S3中更改随机上传的文件名 - Sails.JS

2 个答案: