如何使用定义的范围将键输入数组?

时间:2015-06-23 04:36:49

标签: php arrays associative-array php-5.3 date-range

所以我的代码输出如下:

$test = array('test1.txt' => '1 June 2015',
               'test2.txt' => '1 June 2015',
               'test3.txt' => '1 June 2015',
               'test4.txt' => '1 June 2015',
               'test5.txt' => '1 June 2015');

但是有5个文件而不是5个文件。如何制作,以便我可以根据行号定义输出的日期,即

如果文件1-5(前5个文件),则日期=" 2015年6月1日"。如果文件6-8(接下来的2个文件),则日期=" 2015年6月5日。等等。我将如何这样做?

2 个答案:

答案 0 :(得分:1)

你可以试试这个 -

$date = "1 June 2015"; // The initial date
$fileNum = array(5, 2, 3); // The number of files to be considered
$total = array_sum($fileNum); // Total number of files
$array = array(); // Array to be filled
$j = 1; // The number for increment
foreach($fileNum as $num) {
    $i = 1; // The number to compare the file numbers 
    while($i <= $num) {
         $array['test' . $j . '.txt'] = $date; // Store the values
         $j++;
         $i++;
    }
    $date = date('j F Y', strtotime('+ 1 DAY', strtotime($date))); // Increment the date
}

var_dump($array);

<强>输出

array(10) {
  ["test1.txt"]=>
  string(11) "1 June 2015"
  ["test2.txt"]=>
  string(11) "1 June 2015"
  ["test3.txt"]=>
  string(11) "1 June 2015"
  ["test4.txt"]=>
  string(11) "1 June 2015"
  ["test5.txt"]=>
  string(11) "1 June 2015"
  ["test6.txt"]=>
  string(11) "2 June 2015"
  ["test7.txt"]=>
  string(11) "2 June 2015"
  ["test8.txt"]=>
  string(11) "3 June 2015"
  ["test9.txt"]=>
  string(11) "3 June 2015"
  ["test10.txt"]=>
  string(11) "3 June 2015"
}

<强>更新

$fileNum = array(5 => "1 June 2015", 2 => "2 June 2015", 3 => "3 June 2015"); // Set the array with file number and corresponding dates
$total = array_sum($fileNum);
$array = array();
$j = 1;
foreach($fileNum as $num => $date) {
    $i = 1;
    while($i <= $num) {
         $array['test' . $j . '.txt'] = $date;
         $j++;
         $i++;
    }
}

答案 1 :(得分:0)

试试这个

  $numberOfFiles = 100;
//$startDate = '1 June 2015';

$startDate = '1 June 2015';
for($i=1;$i<=$numberOfFiles;$i++)
{
    if($i%5==0)
    {
        $test['test'.$i.'.txt'] = $startDate;
        $startDate = date('j F Y',strtotime($startDate.' + 5 days'));
    }
    else
    {
        $test['test'.$i.'.txt'] = $startDate;
    } 
}

print_r($test);

已更新至要求。 注意您必须根据文件编号定义日期。

$numberOfFiles = 50;
//$startDate = '1 June 2015';

for($i=1;$i<=$numberOfFiles;$i++)
{
    if($i<=5)
    {
        $startDate ='1 June 2015';
        $test['test'.$i.'.txt'] = $startDate;
    }
    elseif((5<$i)&&($i<=8))
    {
        $startDate ='2 June 2015';
        $test['test'.$i.'.txt'] = $startDate;
    }
    elseif((8<$i)&&($i<=50))
    {
        $startDate ='11 June 2015';
        $test['test'.$i.'.txt'] = $startDate;
    }
    else
    {
        // Define the date value if does not match above criterian
    } 
}

print_r($test);