Question

我想监视文件夹中的某些文件，当有文件更改时，我想捕获该更改并根据此更改我想触发某些程序。

最初我引用了堆栈溢出并使用了一些代码。当我尝试实现时，这不能触发某个程序，但它正在单独捕获更改。

请在下面找到我的代码：

import os, sys, time
from time import gmtime, strftime

def files_to_timestamp(path):
files = [os.path.join(path, f) for f in os.listdir(path)]
return dict ([(f, os.path.getmtime(f)) for f in files])

if __name__ == "__main__":

path_to_watch = r"Desktop\Test\"
print "Watching ", path_to_watch

before = files_to_timestamp(path_to_watch)

while 1:
    time.sleep (2)
    after = files_to_timestamp(path_to_watch)

    added = [f for f in after.keys() if not f in before.keys()]
    removed = [f for f in before.keys() if not f in after.keys()]
    modified = []

    for f in before.keys():
        if not f in removed:
            if os.path.getmtime(f) != before.get(f):
                modified.append(f)

    if added: print "Added: ", ", ".join(added)
    if removed: print "Removed: ", ", ".join(removed)
    if modified:
        file1 = ", ".join(modified)
        print "Updated:",strftime("%Y-%m-%d %H:%M:%S", gmtime()),file1

        if file1 ==                
          'Desktop\Test\L90FLA_TSMC_BE_SBE_THEBE_LOT_MONTHLY_Test.eff':
            execfile(r'H:\Python programs\PSBE_THEBE_New requirments.py')

        elif file1 == 
          'Desktop\Test\L90FLA_TSMC_BE_SBE_CARME_MONTHLY_Test.eff':
            execfile(r'H:\Python programs\PSBE_CARME_New requirments.py')

        elif file1 ==     
          'Desktop\Test\L90FLA_TSMC_BE_SBE_ELARA_LOT_MONTHLY_Test.eff':
            execfile(r'H:\Python programs\PSBE_ELARA_New requirments.py')

    before = after

我请求任何人帮助我。提前谢谢。

Answer 1

您是否尝试过使用inotify API [1]？肯定有它的python接口......

[1] http://man7.org/linux/man-pages/man7/inotify.7.html

监视文件夹内的多个文件更改，然后使用python

1 个答案: