在这个查询中需要帮助任何人都可以为我纠正它JSON给我null 和剂量不解析任何东西到Android应用程序它打印我在neteans测试时所需的值,但不解析值到android
<?php
$nme = (isset($_REQUEST['place_name']) ? $_REQUEST['place_name'] : null);
$con = mysql_connect("localhost","root","");
$db=mysql_select_db("around2",$con);
$result=mysql_query("ٍٍٍٍٍٍSelect
historical_places.city_code , historical_places.address, historical_places.information, historical_places.place_code
,image.image_serial ,image.images
,videos.video_serial ,videos.video_url
FROM historical_places
INNER JOIN image
ON image.place_code=historical_places.place_code
INNER JOIN videos
ON videos.place_code=historical_places.place_code
WHERE historical_places.place_name='$nme'");
while($row = mysql_fetch_assoc($result))
{
$output[]=$row;
}
print(json_encode($output));
mysql_close();
?>
答案 0 :(得分:1)
我不确定这个问题与android有什么关系,但这不可能是正确的:
"ٍٍٍٍSelect