我遇到了使Python套接字服务器从Python套接字客户端接收命令的问题。服务器和客户端可以相互发送文本,但我无法从客户端发送文本触发服务器上的事件。任何人都可以帮助我吗?我使用的是Python 3.4。
server.py
import socket
host = ''
port = 1010
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((host, port))
s.listen(1)
conn, addr = s.accept()
print ("Connection from", addr)
while True:
databytes = conn.recv(1024)
if not databytes: break
data = databytes.decode('utf-8')
print("Recieved: "+(data))
response = input("Reply: ")
if data == "dodo":
print("hejhej")
if response == "exit":
break
conn.sendall(response.encode('utf-8'))
conn.close()
在server.py中,我尝试将单词" dodo"触发print("hejhej")
。
client.py
import socket
host = '127.0.0.1'
port = 1010
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((host, port))
print("Connected to "+(host)+" on port "+str(port))
initialMessage = input("Send: ")
s.sendall(initialMessage.encode('utf-8'))
while True:
data = s.recv(1024)
print("Recieved: "+(data.decode('utf-8')))
response = input("Reply: ")
if response == "exit":
break
s.sendall(response.encode('utf-8'))
s.close()
答案 0 :(得分:1)
这里的一切都很好,但也许不是你想要的方式。如果您在几行上切换订单,它将在您输入服务器响应之前显示您的事件字符串。
import socket
host = ''
port = 1010
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((host, port))
s.listen(1)
conn, addr = s.accept()
print ("Connection from", addr)
while True:
databytes = conn.recv(1024)
if not databytes: break
data = databytes.decode('utf-8')
print("Recieved: "+(data))
if data == "dodo": # moved to before the `input` call
print("hejhej")
response = input("Reply: ")
if response == "exit":
break
conn.sendall(response.encode('utf-8'))
conn.close()