Question

我正在使用Google Analytics的新异步代码，在同一页面中两次调用GA.js是否正确，如果没有，有没有办法做到这一点？

我的问题是我需要使用flash在预订表格上考虑两个PageViews，问题是用户可能无需进入第二阶段但在第一阶段关闭窗口。

  <!-- Step one, I need to record a pageview -->

  var _gaq = _gaq || [];
  _gaq.push(['_setAccount', 'UA-6173481-3']);
  _gaq.push(['_trackPageview', '/Step1']);
  (function() {
   var ga = document.createElement('script'); ga.type = 'text/javascript'; ga.async = true;
   ga.src = ('https:' == document.location.protocol ? 'https://ssl' : 'http://www') +    '.google-analytics.com/ga.js'; 
   var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(ga, s);
   })();

  <!-- Step two of the process i define a function that will get called by flash and record another pageview-->

   function completed (){

   var _gaq = _gaq || [];
   _gaq.push(['_setAccount', 'UA-6173481-3']);
   _gaq.push(['_trackPageview', '/Step2']);
  (function() {
   var ga = document.createElement('script'); ga.type = 'text/javascript'; ga.async = true;
  ga.src = ('https:' == document.location.protocol ? 'https://ssl' : 'http://www') +    '.google-analytics.com/ga.js'; 
  var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(ga, s);
  })();

  }

Answer 1

以下内容应该有效：

  <!-- Step one, I need to record a pageview -->
  var _gaq = _gaq || [];
  _gaq.push(['_setAccount', 'UA-6173481-3']);
  _gaq.push(['_trackPageview', '/Step1']);
  (function() {
   var ga = document.createElement('script'); ga.type = 'text/javascript'; ga.async = true;
   ga.src = ('https:' == document.location.protocol ? 'https://ssl' : 'http://www') +    '.google-analytics.com/ga.js'; 
   var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(ga, s);
   })();

  <!-- Step two of the process i define a function that will get called by flash and record another pageview-->
   function completed (){
   _gaq.push(['_trackPageview', '/Step2']);    
  }

然后在需要时从闪光灯中拨打completed()。

Google Analytics异步代码

1 个答案: