如何避免在每个函数上绑定(this)?

时间:2015-06-18 10:12:43

标签: javascript bind

我正在实施一个构建于OpenLayers3之上的Web地图客户端,该客户端应该能够连接到多个WMS服务器,请求WMS功能并显示服务器公布的层。

var MyMapClient = function(params) {
    this.wms_sources_ = params.wms_sources;
    this.wms_capabilities_ = [];
}

MyMapClient.prototype.parse_capabilities = function(index) {
    var capabilities = this.wms_capabilities_[index];
    // do something with capabilities 
}

MyMapClient.prototype.load_wms_capabilities = function() {
    var parser = new ol.format.WMSCapabilities();

    jQuery.each(this.wms_sources_, (function (index, wms_source) {

        console.log("Parsing " + wms_source.capabilities_url);

        jQuery.when(jQuery.ajax({
            url: wms_source.capabilities_url,
            type: "GET",
            crossDomain: true,
        })).then((function (response, status, jqXHR) {
            var result = parser.read(response);
            console.log("Parsed Capabilities, version " + result.version);
            this.wms_capabilities_[index] = result;
            return index;
        }).bind(this)).then(this.parse_capabilities.bind(this));

    }).bind(this));
};

上面的代码运行正常,但每次我想调用一个需要访问bind(this)实例的“私有”变量的函数时,我必须MyMapClient。在不牺牲可读性的情况下,是否有更好的方法可以始终如一地访问实例内部?

2 个答案:

答案 0 :(得分:7)

我想说要使用两个世界中最好的,即一个保持正确范围的局部变量,并在需要时调用bind()

MyMapClient.prototype.load_wms_capabilities = function() {
    var parser = new ol.format.WMSCapabilities(),
        _this = this;

    jQuery.each(this.wms_sources_, function (index, wms_source) {
        console.log("Parsing " + wms_source.capabilities_url);

        jQuery.when(jQuery.ajax({
            url: wms_source.capabilities_url,
            type: "GET",
            crossDomain: true,
        })).then(function (response, status, jqXHR) {
            var result = parser.read(response);
            console.log("Parsed Capabilities, version " + result.version);
            _this.wms_capabilities_[index] = result;
            return index;
        }).then(
          function() { return _this.parse_capabilities(); }
          // or else
          // _this.parse_capabilities.bind(_this)
          // pick the one you like more
        );
    });
};

答案 1 :(得分:1)

你可以“硬绑定”这样的方法:

function Foo() {
    this.bar = this.bar.bind(this);
}

Foo.prototype.bar = function() {
    return console.log(this.baz);
};

顺便说一句,这就是CoffeeScript在执行此操作时编译的内容:

class Foo
  bar: =>
    console.log @baz

=>运算符会导致保留上下文。