如何与MySQL进行“独特”连接

时间:2010-06-21 21:39:25

标签: mysql join distinct left-join subquery

我想加入两个MySQL表(产品和价格历史记录):

Product表:

Id = int
Name = varchar
Manufacturer = varchar
UPC = varchar
Date_added = datetime

Price_h表:

Id = int
Product_id = int
Price = int
Date = datetime

我可以执行一个简单的LEFT JOIN:

SELECT Product.UPC, Product.Name, Price_h.Price, Price_h.Date
FROM Product
LEFT JOIN Price_h
ON Product.Id = Price_h.Product_id;

但正如预期的那样,如果我在价格历史表中有多个产品条目,我会得到每个历史价格的一个结果。

如何构建一个只返回每个产品的一个实例的连接,只加入与它相关的价格历史表中的最新条目?

5 个答案:

答案 0 :(得分:25)

使用:

   SELECT p.upc,
          p.name,
          ph.price,
          ph.date
     FROM PRODUCT p
LEFT JOIN PRICE_H ph ON ph.product_id = p.id
     JOIN (SELECT a.product_id, 
                  MAX(a.date) AS max_date
             FROM PRICE_H a
         GROUP BY a.product_id) x ON x.product_id = ph.product_id
                                 AND x.max_date = ph.date

答案 1 :(得分:3)

试试这个:

SELECT Product.UPC, Product.Name, Price_h.Price, MAX(Price_h.Date)
 FROM Product
 INNER JOIN Price_h
   ON Product.Id = Price_h.Product_id
GROUP BY Product.UPC, Product.Name, Price_h.Price

答案 2 :(得分:3)

SELECT Product.UPC, Product.Name, Price_h.Price, Price_h.Date
FROM Product
LEFT JOIN Price_h
ON (Product.Id = Price_h.Product_id AND Price_h.Date = 
  (SELECT MAX(Date) FROM Price_h ph1 WHERE ph1.Product_id = Product.Id));

答案 3 :(得分:0)

SELECT n.product_id, 
       n.product_name,
       n.product_articul,
       n.product_price,
       n.product_discount,
       n.product_description, 
       n.product_care,
       (SELECT photo_name FROM siamm_product_photos WHERE product_id = n.product_id LIMIT 1) AS photo_name
FROM siamm_product as n;

答案 4 :(得分:0)

为什么不保持简单快速:

SELECT 
 Product.UPC, Product.Name, Price_h.Price, Price_h.Date
FROM 
 Product
LEFT JOIN 
 Price_h
 ON Product.Id = Price_h.Product_id;
ORDER BY
 Price_h.Date DESC
LIMIT 1