我想加入两个MySQL表(产品和价格历史记录):
Product
表:
Id = int
Name = varchar
Manufacturer = varchar
UPC = varchar
Date_added = datetime
Price_h
表:
Id = int
Product_id = int
Price = int
Date = datetime
我可以执行一个简单的LEFT JOIN:
SELECT Product.UPC, Product.Name, Price_h.Price, Price_h.Date
FROM Product
LEFT JOIN Price_h
ON Product.Id = Price_h.Product_id;
但正如预期的那样,如果我在价格历史表中有多个产品条目,我会得到每个历史价格的一个结果。
如何构建一个只返回每个产品的一个实例的连接,只加入与它相关的价格历史表中的最新条目?
答案 0 :(得分:25)
使用:
SELECT p.upc,
p.name,
ph.price,
ph.date
FROM PRODUCT p
LEFT JOIN PRICE_H ph ON ph.product_id = p.id
JOIN (SELECT a.product_id,
MAX(a.date) AS max_date
FROM PRICE_H a
GROUP BY a.product_id) x ON x.product_id = ph.product_id
AND x.max_date = ph.date
答案 1 :(得分:3)
试试这个:
SELECT Product.UPC, Product.Name, Price_h.Price, MAX(Price_h.Date)
FROM Product
INNER JOIN Price_h
ON Product.Id = Price_h.Product_id
GROUP BY Product.UPC, Product.Name, Price_h.Price
答案 2 :(得分:3)
SELECT Product.UPC, Product.Name, Price_h.Price, Price_h.Date
FROM Product
LEFT JOIN Price_h
ON (Product.Id = Price_h.Product_id AND Price_h.Date =
(SELECT MAX(Date) FROM Price_h ph1 WHERE ph1.Product_id = Product.Id));
答案 3 :(得分:0)
SELECT n.product_id,
n.product_name,
n.product_articul,
n.product_price,
n.product_discount,
n.product_description,
n.product_care,
(SELECT photo_name FROM siamm_product_photos WHERE product_id = n.product_id LIMIT 1) AS photo_name
FROM siamm_product as n;
答案 4 :(得分:0)
为什么不保持简单快速:
SELECT
Product.UPC, Product.Name, Price_h.Price, Price_h.Date
FROM
Product
LEFT JOIN
Price_h
ON Product.Id = Price_h.Product_id;
ORDER BY
Price_h.Date DESC
LIMIT 1