我使用弹出窗口创建新记录,然后在窗口内呈现view
。除此之外,我根据其中组合框的selectedindex在此视图中调用partialview
。我可以成功地将表单发布到Controller并在出现错误时将其返回到视图。但是,在返回表单后,只有view
部分返回,我无法呈现partialview
。那么,我怎样才能在提交表单之前将partialview
呈现为最后一个状态?
查看:
<script src="~/Scripts/jquery.unobtrusive-ajax.min.js"></script>
<div id="target">
@using (Ajax.BeginForm("_Create", "Issue",
new AjaxOptions
{
HttpMethod = "POST",
InsertionMode = InsertionMode.Replace,
UpdateTargetId = "target"
}
))
{
@Html.AntiForgeryToken()
<div class="container">
@Html.ValidationSummary(true)
@Html.LabelFor(m => m.ProjectID)
@(Html.Kendo().DropDownList())
//... some stuff (removed for clarity)
@*Render Partialview according to Dropdownlist's selectedIndex*@
<!-- Place where you will insert your partial -->
<div id="partialPlaceHolder" style="display:none;"></div>
</div>
<div class="modal-footer">
@(Html.Kendo().Button()
.Name("btnCancel")
)
@(Html.Kendo().Button()
.Name("btnSubmit")
)
</div>
}
</div>
<script>
//Render Partialview according to Dropdownlist's selectedIndex
$('#ProjectID').change(function () { /* This is change event for your dropdownlist */
/* Get the selected value of dropdownlist */
var selectedID = $(this).val();
/* Request the partial view with .get request. */
$.get('/Issue/RenderPartialView/' + selectedID, function (data) {
/* data is the pure html returned from action method, load it to your page */
$('#partialPlaceHolder').html(data);
});
});
</script>
答案 0 :(得分:2)
在这种情况下,您需要在没有HTML帮助程序的情况下执行自定义ajax发布。 创建一个普通表单:
<form id="frmEdit" class="form">
@Html.AntiForgeryToken()
<div class="container">
@Html.ValidationSummary(true)
//.... rest form component
<button id="btnSubmit" type="submit">Submit</button>
</div>
</form>
并按照类似这样的jquery发布
<script>
$( "form" ).on( "submit", function( event ) {
event.preventDefault();
$.post(urlPost, $(this).serialize()).done(function(){
// update your target id here and re-fetch your partial view
}).fail(function() {
// show error in validation summary
});
});
</script>
希望此示例可以帮助您解决问题。