这是json的回应:
[
{
"currentvalue": [
{
"id": "13",
"current_value": "0,1",
"create_date": "2015-06-15 06:12:14",
"status": "0",
"modify_date": "0000-00-00 00:00:00",
"entry_time": "",
"indicator_id": "13",
"member_id": "9"
}
],
"target": {
"notification_time": "06:12:14",
"id": "13",
"health_selected_days": {
"day": "3"
},
"point": "1",
"indicator_name": "Test2",
"create_date": "2015-06-15 06:12:14",
"indicator_status": "0",
"notification_type": "0",
"modify_date": "2015-06-15 06:12:14",
"indicator_measure": "0",
"target_value": "0,1",
"total_point": "0",
"member_id": "9"
}
},
{
"currentvalue": [
{
"id": "12",
"current_value": "0,1",
"create_date": "2015-06-15 04:56:22",
"status": "0",
"modify_date": "0000-00-00 00:00:00",
"entry_time": "",
"indicator_id": "12",
"member_id": "9"
}
],
"target": {
"notification_time": "02:02:00",
"id": "12",
"health_selected_days": {
"day": ""
},
"point": "1",
"indicator_name": "Ashish",
"create_date": "2015-06-15 04:56:22",
"indicator_status": "0",
"notification_type": "0",
"modify_date": "2015-06-15 04:56:22",
"indicator_measure": "0",
"target_value": "0,1",
"total_point": "0",
"member_id": "9"
}
},
{
"currentvalue": [
{
"id": "11",
"current_value": "0,1",
"create_date": "2015-06-12 13:58:09",
"status": "0",
"modify_date": "0000-00-00 00:00:00",
"entry_time": "",
"indicator_id": "11",
"member_id": "9"
}
],
"target": {
"notification_time": "02:02:00",
"id": "11",
"health_selected_days": {
"day": "1,2,3,4,5,6,7,"
},
"point": "123",
"indicator_name": "A",
"create_date": "2015-06-12 13:58:09",
"indicator_status": "0",
"notification_type": "0",
"modify_date": "2015-06-12 13:58:09",
"indicator_measure": "0",
"target_value": "0,1",
"total_point": "0",
"member_id": "9"
}
}
]
如何从“target”数组中获取indicator_name值:
答案 0 :(得分:0)
JSONParser parser = new JSONParser();
Object obj = parser.parse(new FileReader("your file path"));
JSONObject jsonObject = (JSONObject) obj;
String name = (String) jsonObject.get("indicator_name");
System.out.println(name);
你可以这样试试。
答案 1 :(得分:0)
for(int i=0; i<jsonArray.length(); i++)
{
JSONObject object = jsonArray.getJSONObject(i);
JSONObject target = object.getJSONObject("target");
String indicator_name = target.getString("indicator_name");
}
target不是数组,实际上它是一个JSONObject。 this site可能有助于使json数据看起来更清晰。
答案 2 :(得分:0)
你可以这样做。
try {
JSONArray _jArrayMain = new JSONArray("YOURJSONSTRING");
for (int i = 0; i < _jArrayMain .length(); i++) {
JSONObject _jObj = _jArrayMain.getJSONObject(i);
JSONObject _jObjTarget = _jObj.getJSONObject("target");
String _indicator_name = _jObjTarget.getString("indicator_name");
System.out.println("Indicator Name : " + _indicator_name);
}
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
答案 3 :(得分:0)
您可以使用以下代码段。
final JSONArray jsonArray = new JSONArray("JSON_STRING");
for (JSONObject jObject: jsoonArray) {
final JSONObject jsonTargetObject = jObject.optJSONObject("target");
if(jsonTargetObject != NULL) {
final String indicatorName = jsonTargetObject.optString("indicator_name", null);
System.out.println("Indicator Name : " + indicatorName);
}
答案 4 :(得分:0)
在您的示例中,
<script src="js/jquery.js"></script>
<script src="js/typed.js"></script>
<script>
$(function() {
$(".element").typed({
image: ['images_folder/foo.png', 'images_folder/bar.png'],
typeSpeed: 30
});
});
</script>