Question

我在将nvarchar转换为int时遇到了一些麻烦。

我想要做的是获得列的最长和最短时间，然后计算AVG时间，但列是nvarchar。

Answer 1

你正在寻找这个吗？

Set Nocount On;

If Object_Id('tempdb.dbo.#sometable') Is Not Null
Begin
    Drop Table #sometable;
End

If Object_Id('tempdb.dbo.#computetable') Is Not Null
Begin
    Drop Table #computetable;
End

Create Table #sometable
(
     RowId          Int Identity(1,1) Primary Key
    ,TimeTaken      Nvarchar(8)
)

Create Table #computetable
(
     RowId          Int Primary Key
    ,ComputeTime    Int
)

Insert Into #sometable(TimeTaken) Values
('15:24:58'),('5:20:08'),('10:14:50'),('21:02:01'),('4:27:30'),('16:21:45')

Insert Into #computetable(RowId,ComputeTime)
Select   st.RowId
        ,(st.HoursToSeconds + st.MinutesToSeconds + st.Seconds) As ComputeTime
From    (
            Select   st.RowId
                    ,(st.Hours * 3600) As HoursToSeconds
                    ,(Cast(Left(st.TimeTaken, (Charindex(':', st.TimeTaken, 0) - 1)) As Int) * 60) As MinutesToSeconds
                    ,Cast(Right(st.TimeTaken, (Charindex(':', st.TimeTaken, 0) - 1)) As Int) As Seconds
            From    (
                        Select   st.RowId
                                ,Cast(Left(st.TimeTaken, (Charindex(':', st.TimeTaken, 0) - 1)) As Int) As Hours
                                ,Substring(st.TimeTaken, (Charindex(':', st.TimeTaken, 0) + 1), Len(st.TimeTaken)) As TimeTaken
                        From    #sometable As st With (Nolock)
                    ) As st
        ) As st

Select   Max(ct.ComputeTime) As HighestTime
        ,Min(ct.ComputeTime) As LowestTime
        ,Avg(ct.ComputeTime) As AvgTime
From    #computetable As ct With (Nolock)

SQL计算AVG时间，但给定时间是NVARCHAR格式

1 个答案: