我正在尝试在d3js中连接两个可拖动的矩形。我的要求是
到目前为止,我可以拖动矩形,如果它们是静态的,我可以连接它们。但是当我在接合它们之后移动矩形时,该线应随矩形移动。
以下是我工作的fiddle。谁能指导我在这里?
var seasons = new object[original.Length];
for (int i = 0; i < original.Length; i++)
{
seasons[i] = original[i];
}
答案 0 :(得分:3)
您需要相应地更新具有属性的行。
以下是一个示例:http://jsfiddle.net/cyril123/kbj4xsmm/12/
var myMapLookup = {c:{ source:'a', target:'b'}};//this will map the line id to its source and target rectangles. this help you track which line is linked to which 2 rectangles.
function move(lineID, me) {
//lineID will gve the id of the line.
var nx = d3.event.x-parseInt(d3.select(me).attr("width"))/2
var ny = d3.event.y-parseInt(d3.select(me).attr("height"))/2
d3.select(me).attr('x', nx)
.attr('y', ny);
//change the line's x and y on dragging
//if source update the x1 and y1
if(d3.select(me).attr('id') == myMapLookup.c.source){
d3.select('#' + lineID).attr('x1', nx).attr('y1', ny);
}
//if source update the x2 and y2
if(d3.select(me).attr('id') == myMapLookup.c.target){
d3.select('#' + lineID).attr('x2', nx).attr('y2', ny);
}
}
d3.select("#a").on('mousedown', function(d){
d3.select("#c").style("display","");//make the line visible when mouse click is down.
d3.select("#c").data({src: 'a', target: 'b'})
});
d3.select("#b").on('mouseup', function(d){
d3.select('#c')
.attr('x2', 400)
.attr('y2', 400);
//remove all the listeners as we have made the connection line
d3.select("#main").on('mousemove',null);
d3.select("#a").on('mousedown',null);
d3.select("#b").on('mouseup',null);
//attach drag listener to all rectangles
var dragA = d3.behavior.drag().on("drag", function(){move('c', this)});
d3.select("#a").call(dragA);
var dragB = d3.behavior.drag().on("drag", function(){move('c', this)});
d3.select("#b").call(dragB);
});
d3.select("#main").on('mousemove', function(d){
//on mouse move update the line.
var mouseLoc = d3.mouse(this);
d3.select('#c')
.attr('x2', mouseLoc[0]-5)
.attr('y2', mouseLoc[1]-5);
});
您可以使用myMapLookup来修改源和目标矩形的行。 通过这种方式,您可以拥有n个矩形,并且可以使用n行和相同的拖动代码。