在this page上,每个团队的最终得分(数字)具有相同的班级名称class="finalScore"
。
当我打电话给客队的最终得分(在顶部)时,代码会毫无问题地调用该号码。如果...... favLastGM ='A'
当我试图调用主队的最终得分时(在底部),代码给我一个错误。如果...... favLastGM ='H'
以下是我的代码:
import pickle
import math
import urllib2
from lxml import etree
from bs4 import BeautifulSoup
from urllib import urlopen
#Last Two Game info Home [H] or Away [A]
favLastGM = 'A' #Higher week number 2
#Game Info (Favorite) Last Game Played - CBS Sports (Change Every Week)
favPrevGMInfoUrl = 'http://www.cbssports.com/nfl/gametracker/boxscore/NFL_20140914_NE@MIN'
favPrevGMInfoHtml = urlopen(favPrevGMInfoUrl).read()
favPrevGMInfoSoup = BeautifulSoup(favPrevGMInfoHtml)
if favLastGM == 'A': #This Gives Final Score of Away Team - Away Score
favScore = favPrevGMInfoSoup.find_all("td", { "class" : "finalScore" })
elif favLastGM == 'H':
favScore = favPrevGMInfoSoup.find_all("td", { "class" : "finalScore" })[1]
else:
print("***************************************************")
print("NOT A VALID ENTRY - favLastGM !")
print("***************************************************")
print ("Enter: Total Points Allowed from Favored Team Defense for last game played: "),
print favScore[0].text
如果favLastGM ='H'
,这是我得到的错误Traceback(最近一次调用最后一次):文件 “C:/Users/jcmcdonald/Desktop/FinalScoreTest.py”,第26行,in print favScore [0] .text文件“C:\ Python27 \ lib \ site-packages \ bs4 \ element.py”,第905行,in 的的GetItem return self.attrs [key] KeyError:0
答案 0 :(得分:2)
class="finalScore"
只有两个元素,第一个是主队得分,第二个是客队得分:
>>> from urllib import urlopen
>>> from bs4 import BeautifulSoup
>>>
>>> favPrevGMInfoUrl = 'http://www.cbssports.com/nfl/gametracker/boxscore/NFL_20140914_NE@MIN'
>>>
>>> favPrevGMInfoSoup = BeautifulSoup(urlopen(favPrevGMInfoUrl))
>>> score = [item.get_text() for item in favPrevGMInfoSoup.find_all("td", {"class": "finalScore"})]
>>> score
[u'30', u'7']
仅供参考,而不是.find_all("td", {"class": "finalScore"})
,您可以使用CSS selector:.select("td.finalScore")
。
答案 1 :(得分:0)
在您的代码中,您要为favScore
分配不同类型的对象。所以在第一种情况下,你有:
if favLastGM == 'A': #This Gives Final Score of Away Team - Away Score
favScore = favPrevGMInfoSoup.find_all("td", { "class" : "finalScore" })
你最终得到一个清单......
faveScore = [<td class="finalScore">30</td>, <td class="finalScore">7</td>]
而在第二种情况下,你有:
elif favLastGM == 'H':
favScore = favPrevGMInfoSoup.find_all("td", { "class" : "finalScore" })[1]
你最终得到了一个BeautfulSoup元素......
favScore = <td class="finalScore">7</td>
您可以通过执行此操作来解决此问题(请注意[0]
):
if favLastGM == 'A': #This Gives Final Score of Away Team - Away Score
favScore = favPrevGMInfoSoup.find_all("td", { "class" : "finalScore" })[0]
elif favLastGM == 'H':
favScore = favPrevGMInfoSoup.find_all("td", { "class" : "finalScore" })[1]
然后在最后做:
print favScore.text
答案 2 :(得分:0)
我轻微扩展到@ alecxe的答案,明确选择 home 和 away 团队(而不是依赖于数组的隐式排序):
from urllib import urlopen
from bs4 import BeautifulSoup
favPrevGMInfoUrl = 'http://www.cbssports.com/nfl/gametracker/boxscore/NFL_20140914_NE@MIN'
favPrevGMInfoSoup = BeautifulSoup(urlopen(favPrevGMInfoUrl))
home_score = favPrevGMInfoSoup.find("tr", {"class": "teamInfo homeTeam"}).find("td", {"class": "finalScore"}).get_text()
away_score = favPrevGMInfoSoup.find("tr", {"class": "teamInfo awayTeam"}).find("td", {"class": "finalScore"}).get_text()
print home_score, away_score