Question

我正在开发一家披萨店的电子商务电子商务，现在我正试图获得规模（熟悉）和成分（Pernildol�，之前订购的披萨的Bac�，Emmental ）。我想要获取的数据（本段中的斜体值）从数据库序列化：

import networkx as nx
import matplotlib.pyplot as plt
import numpy as np

# define nodes, node types, and color range
np.random.seed(10000)
nodes = list('abcdefghijkl')
nodeTypes = ['foo','bar','baz']
nodeColors = [0.0, 0.5, 1.0]

# assign each node a type and color via a dictionaries
nodeTypeDict = dict(zip(nodeTypes, [nodes[:4],nodes[4:8],nodes[8:]]))
nodeColorDict = dict(zip(nodeTypes, nodeColors))
nodePos = dict(zip(nodes,[(np.random.random(),np.random.random()) 
                                        for i in range(len(nodes))]))

# generate the graph
g = nx.Graph()
g.add_nodes_from(nodes)

# create image canvas and axes
fig, ax = plt.subplots(1, figsize=(6,6))

# iterate each nodetype, changing colors and labels of the nodes
for nt in nodeTypes:
    # choose nodes and color for each iteration
    nlist = nodeTypeDict[nt]
    ncolor = [nodeColorDict[nt]]*len(nlist)
    # draw the graph
    nx.draw_networkx_nodes(g, 
                           pos=nodePos,
                           nodelist=nlist,
                           ax=ax, 
                           cmap=plt.cm.brg, 
                           vmin=0.0,
                           vmax=1.0,
                           node_color=ncolor,
                           label=nt)  # the label for each iteration is 
                                      # the node type

# here is the problem.  The legend does not inherit the colors.
ax.legend(scatterpoints=1)
plt.show()

我发现＆＃39;反序列化＆＃39; php方法，我试过这个：

a:4:{s:10:"attributes";a:2:{s:6:"Tamany";a:1:{i:3;s:8:"Familiar";}s:11:"Ingredients";a:3:{i:318;s:12:"Pernil dol�";i:270;s:5:"Bac�";i:294;s:8:"Emmental";}}s:9:"shippable";s:1:"0";s:4:"type";s:5:"pizza";s:6:"module";s:10:"uc_product";}array(4) { ["attributes"]=> array(2) { ["Tamany"]=> array(1) { [3]=> string(8) "Familiar" } ["Ingredients"]=> array(3) { [318]=> string(11) "Pernil dol�" [270]=> string(4) "Bac�" [294]=> string(8) "Emmental" } } ["shippable"]=> string(1) "0" ["type"]=> string(5) "pizza" ["module"]=> string(10) "uc_product" }

在我这样做之后，我得到了这个多维数组（更具人性化）：

$attr = $row['data']; // data from database
$data = preg_replace('!s:(\d+):"(.*?)";!e', "'s:'.strlen('$2').':\"$2\";'", $attr); // I did this because I get some errors...

下一步是尝试使用foreach循环循环结果数据，如下所示：

array(4) { ["attributes"]=> array(2) { ["Tamany"]=> array(1) { [3]=> string(8) "Familiar" } ["Ingredients"]=> array(3) { [318]=> string(11) "Pernil dol�" [270]=> string(4) "Bac�" [294]=> string(8) "Emmental" } } ["shippable"]=> string(1) "0" ["type"]=> string(5) "pizza" ["module"]=> string(10) "uc_product" }

我是一名php初学PHP开发人员，我无法弄清楚如何循环这个数组以获得我需要的值。我收到此错误：

foreach($data['attributes'] as $item)
  {
    print '<ul>';

    foreach($item as $value)
    {
        print_r('<li>' . $value . '</li>');
    }

    print '</ul>';
  }

有人能告诉我如何循环这个数组来获取数据吗？任何帮助都将非常非常感激。

致以最诚挚的问候，

Answer 1

我为你创建了这个例子。首先，我声明了一个数组，它相信模仿你必须解析的数组。然后我循环并输出数组的内容。

<?php

$array = array(
    0 => array(
        '0' => 'John Doe',
        '1' => 'john@example.com'
    ),
    1 => array(
        '0' => 'Jane Doe',
        '1' => 'jane@example.com'
    ),
);  

foreach ($array as $key => $value) {

    $thisArray = $array[$key];

    print_r('<ul>');
    foreach ($thisArray as $key2 => $value){
      print_r('<li>'.$thisArray[$key2].'</li>');
    }
    print_r('</ul>');
}
?>

Answer 2

最后，根据@Gregory Hart的答案，我达到了目标。这是在我的特定情况下可以实现的最终代码：

$data = $row['data'];
  $attrib = preg_replace('!s:(\d+):"(.*?)";!e', "'s:'.strlen('$2').':\"$2\";'", $data);
  $attr = unserialize($attrib);

  foreach ($attr as $key => $value)
  {
      print_r('<ul>');
      $thisArray = $attr[$key];

      foreach ($thisArray as $key2 => $value2)
      {
        print_r('<li>' . $key2 . ': ');
        $thisArray2 = $attr[$key][$key2];

        foreach ($thisArray2 as $key3 => $value3)
        {
          if ($key2 == 'Tamany')
            print_r('<span class="label label-warning">' . utf8_encode($thisArray2[$key3]) . '</span> ');
          if ($key2 == 'Ingredients')
            print_r('<span class="label label-success">' . utf8_encode($thisArray2[$key3]) . '</span> ');
          if ($key2 == 'Salsa')
            print_r('<span class="label label-primary">' . utf8_encode($thisArray2[$key3]) . '</span> ');
        }
        print '</li>';
      }
      print_r('</ul>');
  }

谢谢你的帮助！

如何使用php循环并从数据库获取序列化值

2 个答案: