Question

我正在尝试创建此列表的字符串而不使用以下字符, []，因为我想在删除它们之后替换所有两个空格。

我已尝试过以下内容，但我正在考虑标题中的错误。的简单：

[06:15, 06:45, 07:16, 07:46]

结果应如下所示：

06:15 06:45 07:16 07:46

代码：

List<String> value = entry.getValue();
String timeEntries = value.toString();
String after = timeEntries.replaceAll(",", " ");
String after2 = after.replaceAll("  ", " ");
String after3 = after2.replaceAll("[", "");
String after4 = after3.replaceAll("]", "");

Answer 1

replaceAll会替换与给定正则表达式匹配的所有匹配项。由于您只想匹配一个简单的字符串，因此您应该使用replace代替：

void OnGUI(){
    if (visible) {
        GUI.skin = skin;

        GUI.Window(0,new Rect((Screen.width-1024)/2,0,1024,600),InventoryBody,"Inventory");
    }
}

void InventoryBody(int id){
    GUIStyle style = new GUIStyle();

    if (currentItem) {
        GUI.DrawTexture (new Rect(550f,70f,80f,80f), currentItem.texture);
        GUI.color = Color.red;


        GUI.Label (new Rect(700f,50f,400f,300f), currentItem.name);

        GUI.color = Color.black;

        string desc = "Description: "+currentItem.description;

        style.wordWrap=true;
        style.fontSize=18;

        GUI.Label (new Rect(650f,100f,300f,500f), desc,style);


        if(GUI.Button(new Rect(700f, 290f, 150f,50f), "Cancel")) {
            currentItem = null;

        }


        if(GUI.Button(new Rect(700f, 230f, 150f,50f), "Use")) {
            currentItem.Use ();
        }
    }

    //1st column
    GUILayout.BeginArea (new Rect (80f,60f,600f,600f));

    for (int i = 0; i<5; i++) {
        if(items[i]!=null){

            if(GUILayout.Button (items [i].texture, GUILayout.Width (80f), GUILayout.Height (80f)) ){
                currentItem = items[i];
            }


        } else {
            GUILayout.Box("", GUILayout.Width(80f),GUILayout.Height(80f));
        }
    }

    GUILayout.EndArea ();

    //2nd column
    GUILayout.BeginAr...
}

Answer 2

要回答主要问题，如果您使用replaceAll，请确保您的第一个参数是有效的正则表达式。对于您的示例，您实际上可以将其减少为2次调用replaceAll，因为其中2次替换相同。

List<String> value = entry.getValue();
String timeEntries = value.toString();
String after = timeEntries.replaceAll("[, ]", " ");
String after2 = after.replaceAll("\\[|\\]", "");

但是，看起来你只是试图将String列表的所有元素连接在一起。通过迭代列表并使用StringBuilder：

，直接构造此字符串会更有效

StringBuilder builder = new StringBuilder();

for (String timeEntry: entry.getValue()) {
  builder.append(timeEntry);
}

String after = builder.toString();

替换String对象中的字符时出现Java PatternSyntaxException

2 个答案: