Question

我需要将此值发布到另一个php页面并显示值。我怎么做？

PHP：

if(!empty($_POST["mytext"])) {
  for ($x=1; $x<=$a; $x++) { 
    echo $txtLine[$x] = $_POST['mytext'.$x]; 
  }
}

代码：

＆＃13;

function popuptxt() {
  var i = _("no_room").value;
  my_div.innerHTML = "";
  for (a = 1; a <= i; a++) {
    my_div.innerHTML = my_div.innerHTML + 
      " <input type='text' style='width:50px;' name='mytext'+a> "
  }
}

＆＃13;

<form method="post" action="getvalue.php">
  <input type="text" style="width:200px;" 
     id="no_room" name="no_room" onChange="popuptxt()" required>
  <div id="my_div"></div>
</form>

＆＃13;

Answer 1

将此更新为您的javascript

function popuptxt() {
      var i = _("no_room").value;
      my_div.innerHTML = "";
      for (a = 1; a <= i; a++) {
        my_div.innerHTML = my_div.innerHTML + 
          " <input type='text' style='width:50px;' name='mytext[]'> "
      }
    }

将此更新到您的php

if(!empty($_POST["mytext"])) {
  foreach ($_POST["mytext"] as $mytext) { 
    echo $txtLine[] = $mytext; 
  }
}

它可能适用于您的病情

如何在动态弹出文本框中发布值

1 个答案: