Question

我有一些（可能很多）类很简单的类

KeyValuePair<string,string>

没有通用接口，但它们没有方法只是属性。

我希望能够将这样的任何类型转换为具有属性名称的{{1}}和设置的值。

无论如何都在做这件可怕的事情！？

Answer 1

彼得打败了我，但这是一个快速的linqpad：

void Main()
{
    GetValues(new ResultA
    {
        Date = DateTime.Now,
        Year = 2000
    }).Dump();
}

public IDictionary<string, string> GetValues(object obj) 
{
    return obj
            .GetType()
            .GetProperties()
            .ToDictionary(p=>p.Name, p=> p.GetValue(obj).ToString());
}

public class ResultA
{
    public DateTime Date { get; set; }
    public int Year { get; set; }
    public int Month { get; set; }
    public int Day { get; set; }
}

输出

Key   Value
Date  10-Jun-15 14:48:11 
Year  2000 
Month 0 
Day   0

Answer 2

使用这样的反射：

[Test]
public void DoStuff() {
  List<object> things = new List<object>() {
    new ResultA(){Date = DateTime.Now, Month = 34}, new ResultB(){Count = 1, Jewels = 4, Number = "2", Update = "0"}
  };

  foreach (var thing in things) {
    foreach (var property in thing.GetType().GetProperties()) {
      Trace.WriteLine(property.Name + " " + property.GetValue(thing));
    }
  }
}

输出：

Date 10.06.2015 13:46:41
Year 0
Month 34
Day 0
Number 2
Count 1
Update 0
Jewels 4

您还可以使用扩展方法：

public static class ObjectExtensions {
  public static List<KeyValuePair<string, object>> GetProperties(this object me) {
    List<KeyValuePair<string, object>> result = new List<KeyValuePair<string, object>>();
    foreach (var property in me.GetType().GetProperties()) {
      result.Add(new KeyValuePair<string, object>(property.Name, property.GetValue(me)));
    }
    return result;
  }
}

用法：

  [Test]
  public void DoItWithExtensionMethod() {
    List<object> things = new List<object>() {
    new ResultA(){Date = DateTime.Now, Month = 34}, new ResultB(){Count = 1, Jewels = 4, Number = "2", Update = "0"}
    };

    foreach (var thing in things) {
      var properties = thing.GetProperties();
      foreach (var property in properties) {
        Trace.WriteLine(property.Key + " " + property.Value);
      }
    }
  }

将任何类转换为keyvaluepair

2 个答案: