Question

我想将列表项分成两个列表。

a = [[1, 0, 2], [0, 0, 0], [1], [1]]
b = [[5, 6, 4], [6, 6, 6], [3], [3]]

如何将a除以b来获得此输出：

c = [[0.2, 0, 0.5], [0, 0, 0], [0.333], [0.333]]

任何人都可以帮助我吗？

Answer 1

压缩两个列表并使用列表解析：

from __future__ import division   # in python2 only
result = [[x/y for x,y in zip(xs, ys)] for xs, ys in zip(a, b)]

示例运行：

In [1]: a = [[1, 0, 2], [0, 0, 0], [1], [1]]
   ...: b = [[5, 6, 4], [6, 6, 6], [3], [3]]
   ...: 

In [2]: result = [[x/y for x,y in zip(xs, ys)] for xs, ys in zip(a, b)]

In [3]: result
Out[3]: [[0.2, 0.0, 0.5], [0.0, 0.0, 0.0], [0.3333333333333333], [0.3333333333333333]]

Answer 2

使用itertools.izip（Python2.7）：

import itertools

[[float(aaa) / bbb for (aaa, bbb) in itertools.izip(aa, bb)] \
    for (aa, bb) in itertools.izip(a, b)]

Answer 3

from __future__ import division # for Python2

[[x / y for x, y  in zip(*item)] for item in zip(a, b)]

如何使用Python将列表项从另一个列表中除以列表项？

3 个答案: