Question

我正在尝试使用if else语句在我的首选列表中突出显示一个网站。当我检查服务器的元素，它应该是赞助商网站时，它不会显示为“赞助商网站”css，它仍然以闪烁（赞助商= 0）的形式出现。我不确定我是否真的在检查该网站是否是赞助商？

<?php
require_once('mysql_connect.php');

$query  =   "SELECT id, name, banner, description, sponsor, votes, hits FROM websites ORDER BY votes DESC LIMIT 50";
$result =   mysql_query($query) OR die(mysql_error());
// Rank counter
$rank = 1;
while($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
    //it would wrap your text upto 20 characters 
    $wrappedText = wordwrap(substr($row['description'], 0, 200), 55, "<br />\n", true);

    if(sponsor == 0){
        echo '<tbody>
    <tr class="server glossed site">
        <td class="rank hidden-sm hidden-xs">
        '.$rank.'</td>
        <td class="description"><p><a href="out.php?id='.$row['id'].'" target="_blank">'.$row['name'].'<br /><p><a href="out.php?id='.$row['id'].'" rel="no_follow" target="_blank"><img src="'.$row['banner'].'" width="470" height="60"></a></p></a><br><p class="hidden-sm hidden-xs">'.
        $wrappedText.'</p></td>
        <td class="votes hidden-sm hidden-xs">'.$row['votes'].'</td>
    </tr>';
    } else {
        echo '<tbody>
    <tr class="server sponsor site">
        <td class="rank hidden-sm hidden-xs">
        '.$rank.'</td>
        <td class="description"><p><a href="out.php?id='.$row['id'].'" target="_blank">'.$row['name'].'<br /><p><a href="out.php?id='.$row['id'].'" rel="no_follow" target="_blank"><img src="'.$row['banner'].'" width="470" height="60"></a></p></a><br><p class="hidden-sm hidden-xs">'.
        $wrappedText.'</p></td>
        <td class="votes hidden-sm hidden-xs">'.$row['votes'].'</td>
    </tr>';
    }
$rank++;
}
?>

Answer 1

你可能也看到了PHP错误。无论哪种方式，你的while语句都会循环查询结果，因为它是一个数组因此，你必须改变

if(sponsor == 0){

到

if ($row['sponsor'] == 0) {

这应该会给你预期的结果。

使用if else显示赞助商，不显示PHP

1 个答案: