Question

我目前的代码如下，我想要发生的是点击按钮后我希望它转到一个空白页面，中间印有“Hello”。代码如下：

#!/usr/local/bin/python3.4
import pygame, sys
from pygame.locals import *
windowHeight = 600
windowWidth = 900

def main():
    pygame.init()
    screen = pygame.display.set_mode((windowWidth, windowHeight))
    pygame.display.set_caption('Test')
    background = pygame.image.load('background.jpg')
    screen.blit(background, (0,0))
    face = pygame.image.load('text.gif')
    b = screen.blit(face, (300, 300))

    while 1:
        for event in pygame.event.get():
            if event.type == QUIT:
                pygame.quit()
                sys.exit()
            if event.type == pygame.MOUSEMOTION:
                x, y = event.pos
                if b.collidepoint(x, y):
                    face = pygame.image.load('background.jpg')
                    b = screen.blit(face, (300, 300))
                else: 
                    face = face = pygame.image.load('text.gif')
                    b = screen.blit(face, (300, 300))
            if event.type == pygame.MOUSEBUTTONDOWN and event.button == 1:
                x, y = event.pos
                if b.collidepoint(x, y):
                    print("button has been clicked")

        pygame.display.update()

if __name__ == '__main__': 
    main()

Answer 1

您可以使用标签创建新类，例如HelloWorld：＆＃34; Hello world＆＃34;并在您发布类HelloWorld时创建函数。例如（Python 2.7）：

if __name__ == "__main__":
    def _creator():        
        screen2 = pygame.display.set_mode((SCREEN_WIDTH, SCREEN_HEIGHT),0,32)
        hello = HelloWorld(screen2)
        hello.run()
    MENU_ITEMS = ("Welcome", "Exit")
    SCREEN = pygame.display.set_mode((800, 600), 0, 32)
    FUNCS = {"Welcome": _creator, "Exit": sys.exit}
    GM = Main(SCREEN, FUNCS.keys(), FUNCS)
    GM.run()

当您点击＆＃34;欢迎＆＃34;你启动了HelloWorld类。

如何在pygame中创建一个新窗口？

1 个答案: