Question

我在laravel 4中遇到了whereNotIn的问题，我需要将其从ids的数组中删除，如下所示

 $studAttend  = StudentAttendees::select('subject_schedule_id')->distinct()->get();

$Check  = SubjectSchedule::whereNotIn('id', array($studAttend))->get();

此外，我尝试将代码更改为$studAttend，如下所示

$studAttendArray = array();

foreach ($studAttend as $stdAtt)
{
    $studAttendArray [] = $stdAtt ; 
}

成为

$Check  = SubjectSchedule::whereNotIn('id', $studAttendArray)->get();

$Check变量的结果返回null []的问题，但是当我使用以下手动代码时$Check返回我需要它的行的结果

$Check  = SubjectSchedule::whereNotIn('id', array(1,2,3,4,5,6,7 ))->get();

注意数组中的上述数字与$studAttend或$stuAttendArray的结果相同。

任何建议？

Answer 1

I Solved It just by using toArray() as bellow

$Check  = SubjectSchedule::whereNotIn('id', $studAttend->toArray());

Now not return []

Answer 2

功能看起来很好，你只需要确保传入正确的数组。

此代码应该更容易一些：

// lists will return an actual array with just the field specified as the values.
// array_unique will make sure the values are unique.
$studAttend = array_unique(StudentAttendees::lists('subject_schedule_id'));

// pass the array to your next query
$Check = SubjectSchedule::whereNotIn('id', $studAttend)->get();

Answer 3

你可以使用不喜欢的地方

$Check  = SubjectSchedule::whereIn('id', '!=', $studAttendArray)->get();

哪些不在Laravel 4

3 个答案: