Question

这是我的html代码，现在我想要使用漂亮的汤来提取下面的html代码数据

<tr class="tr-option">
<td class="td-option"><a href="">A.</a></td>
<td class="td-option">120 m</td>
<td class="td-option"><a href="">B.</a></td>
<td class="td-option">240 m</td>
<td class="td-option"><a href="">C.</a></td>
<td class="td-option" >300 m</td>
<td class="td-option"><a href="">D.</a></td>
<td class="td-option" >None of these</td>
</tr>

这是我美丽的汤代码

soup = BeautifulSoup(html_doc)
for option in soup.find_all('td', attrs={'class':"td-option"}):
    print option.text

上述代码的输出：

A.
120 m
B.
240 m
C.
300 m
D.
None of these

但我想要关注输出

A.120 m
B.240 m
C.300 m
D.None of these

我该怎么办？

Answer 1

由于find_all会返回一个选项列表，您可以使用列表推导来获得您期望的答案

>>> a_list = [ option.text for option in soup.find_all('td', attrs={'class':"td-option"}) ]
>>> new_list = [ a_list[i] + a_list[i+1] for i in range(0,len(a_list),2) ]
>>> for option in new_list:
...     print option
... 
A.120 m
B.240 m
C.300 m
D.None of these

它的作用是什么？

[ a_list[i] + a_list[i+1] for i in range(0,len(a_list),2) ]从a_list获取相邻元素并附加它们。

Answer 2

soup = BeautifulSoup(html_doc) 
options = soup.find_all('td', attrs={'class': "td-option"}) 
texts = [o.text for o in options] 
lines = [] 
# Add every two-element pair as a concatenated item
for a, b in zip(texts[0::2], texts[1::2]): 
    lines.append(a + b)
for l in lines:
    print(l)

给予

A.120 m
B.240 m
C.300 m
D.None of these

美丽的汤：从HTML获取文本数据

2 个答案: