Question

我的JSON对象

$scope.selectedItems ={
    "RECORDS": [
        {
            "Id": 23040035705987,
            "arriveddate": "2015/04/24",
            "expirationDate": null,
            "replacedDate": null,
            "processDate": "2015/04/24"
        },
        {
            "Id": 23070041800654,
            "arriveddate": "2015/04/24",
            "expirationDate": null,
            "replacedDate": null,
            "processDate": "2015/04/27"
        },
        {
            "Id": 23040035705984,
            "arriveddate": "2015/04/24",
            "expirationDate": null,
            "replacedDate": null,
            "processDate": "2015/04/24"
        },
        {
            "Id": 23040035705983,
            "arriveddate": "2015/04/24",
            "expirationDate": null,
            "replacedDate": null,
            "processDate": "2015/04/24"
        }
    ]
}

我在尝试什么

对于我所拥有的每个独特的过程日期，我需要在下面提到的对象中的单独对象中使用相应的ID，过程日期24/04/2015与以83,84,87结尾的过程日期和过程日期27/04相匹配/ 2015匹配以54结尾的id

我期望的JSON对象

{
    "processDate": [
        "2015/04/24",
        "2015/04/27"
    ],
    "Id": [
        [
            23040035705983,
            23040035705984,
            23040035705987
        ],
        [
            23070041800654
        ]
    ]
}

我的尝试

angular.forEach($scope.selectedItems.RECORDS, function ( item ) { 
                $scope.ProcessDate = item.processDate;
                if($scope.processDatesSelected.indexOf($scope.ProcessDate) == -1){
                  $scope.processDatesSelected.push($scope.ProcessDate);
                }

                if($scope.processDatesSelected.indexOf($scope.ProcessDate) != -1 && $scope.id.indexOf(item.Id) == -1 ){
                    $scope.id.push(item.Id);
                }

            });

  $scope.changesSelected.push({processDate:$scope.processDatesSelected,Ids:$scope.id});
  console.log(JSON.stringify($scope.changesSelected));

问题是id没有相应的映射，我为同一个创建了一个plunker（http://plnkr.co/edit/mkLXdOKayaqyDDDheFeu?p=preview）任何帮助将不胜感激。

Answer 1

尝试这种方式：http://plnkr.co/edit/LS40YJR9X0OAqBTIP2lZ?p=preview

angular.forEach($scope.selectedItems.RECORDS, function ( item ) { 
            $scope.ProcessDate = item.processDate;
            var i=$scope.processDatesSelected.indexOf($scope.ProcessDate);
            if(i == -1){
              i=$scope.processDatesSelected.length;
              $scope.processDatesSelected.push($scope.ProcessDate);
              $scope.id[i]=[];
            }

            if(i != -1 && $scope.id[i].indexOf(item.Id) == -1 ){
                $scope.id[i].push(item.Id);
            }

        });

Answer 2

您想为每个日期创建数组，因此您应该在创建id数组期间的那个日期使用int帐户

检查一下： http://plnkr.co/edit/vrig4P9SgZh8Kk7BkyEt?p=preview

首先，您必须从第一个数组中找到项目索引，然后将您的元素添加到正确的位置。

var processDateIndex = $scope.processDatesSelected.indexOf($scope.ProcessDate);
if(processDateIndex != -1 && $scope.id.indexOf(item.Id) == -1 ){
  if ($scope.id.length < processDateIndex+1)
  {
    $scope.id.push([]);
  }
    $scope.id[processDateIndex].push(item.Id);
}

你也可以使用这样的结构。它可以帮助您轻松维护此系列：

{
    "processDate": [
        { 
            Date: "2015/04/24",
            Ids: [
                23040035705983,
                23040035705984,
                23040035705987
            ]
        },
        {
            Date: "2015/04/27",
            Ids: [
                23070041800654
            ]
        }
    ]
}

Answer 3

这应该可以解决问题：

var result = {
    processDate: [],
    Id: []
};

for(var i = 0; i < $scope.selectedItems.RECORDS.length; i++) {
    var record = $scope.selectedItems.RECORDS[i],
        index = result.processDate.indexOf(record.processDate);
    if(index === -1) {
        result.processDate.push(record.processDate);
        result.Id.push([record.Id]);
    } else {
        result.Id[index].push(record.Id);
    }
}

Angular中的数组映射

3 个答案: