我经常使用twitter4j获得以下异常:
2015-06-02 10:04:30,802 DEBUG [Twitter Stream consumer-1[Establishing connection]] TwitterBot(116): Got an exception 420:Returned by the Search and Trends API when you are being rate limited (https://dev.twitter.com/docs/rate-limiting).
Returned by the Streaming API:
Too many login attempts in a short period of time.
Running too many copies of the same application authenticating with the same account name.
Exceeded connection limit for user
由于我试图避免被Twitter禁止,我想问一下,如果我在我的代码中做错了什么:
我在Stream API上使用StatusListener,它由我自己的ID和一些字符串值过滤。
如果状态符合条件,则通过Twitter发送此状态的答案。这种情况不会经常发生,因此这不应该是速率限制例外的问题。
如果这很重要,整个事情都在TomEE EJB环境中运行?
@Startup
@Singleton
public class TwitterBot implements Service {
private static final org.slf4j.Logger logger = org.slf4j.LoggerFactory.getLogger(TwitterBot.class);
//this is fix for this twitter bot
public static final String TWITTER_BOT_NAME = "botname";
public static final long TWITTER_BOT_USER_ID = 99999L; //the bot's user id
private final TwitterStream twitterStream;
private final Twitter twitter;
public TwitterBot() {
this.twitterStream = new TwitterStreamFactory().getInstance();
this.twitter = TwitterFactory.getSingleton();
}
@PostConstruct
public void listen() {
StatusListener listener = new StatusListener() {
@Override
public void onStatus(Status status) {
//this is to avoid a circle... ignore tweets coming from ourselves.
if (status.getUser().getScreenName().equalsIgnoreCase(TWITTER_BOT_NAME)) {
return;
}
try {
//do something and update own status
StatusUpdate update = new StatusUpdate("Hello World!");
update.setInReplyToStatusId(status.getId());
twitter.updateStatus(update);
} catch (TwitterException e) {
logger.error("Could not complete twitter update, {}", e.getLocalizedMessage(), e);
}
}
//other Status Listener methods, which are not used (default implementation)
};
//filtering for ourselves here
long[] userFilter = {TWITTER_BOT_USER_ID};
String[] termFilter = {TWITTER_EXPERTIZER_BOT_NAME};
FilterQuery filter = new FilterQuery(0, userFilter, termFilter);
twitterStream.addListener(listener);
twitterStream.filter(filter);
}
}
这个How to handle rate limit using twitter4j to avoid being banned的答案告诉我,Streaming API没有速率限制。
那么问题是什么? API文档中有解释吗?
提前谢谢!
答案 0 :(得分:1)
编辑:
问题与
有关FilterQuery filter = new FilterQuery(0, userFilter, termFilter);
使用这样的查询会在Twitter API上产生某种轮询,因此超出了连接限制。
改为使用:
FilterQuery filter = new FilterQuery(termFilter);