如何避免“Root WebApplicationContext:初始化启动”加载两次?

时间:2015-05-31 20:04:40

标签: java spring spring-mvc tomcat

我正在使用Spring MVC,Spring安全性并在Apache Tomcat 1.7x中进行部署。我注意到Web应用程序上下文被加载了两次。请让我知道我的配置有什么问题。

我在下面的帖子中提到过,但无法确定差异 Why Spring Context is loaded twice?Spring MVC web app: application context starts twice

  

INFO ContextLoader:273 - Root WebApplicationContext:初始化   开始

以下是我的 web.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
    xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security.xsd
            http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">

    <beans:bean id="roleVoter"
        class="org.springframework.security.access.vote.RoleVoter">
        <beans:property name="rolePrefix" value=""></beans:property>
    </beans:bean>
    <beans:import resource="servlet-context.xml" />

    <beans:bean id="accessDecisionManager"
        class="org.springframework.security.access.vote.AffirmativeBased">
        <beans:constructor-arg name="decisionVoters"
            ref="roleVoter" />
    </beans:bean>

    <http authentication-manager-ref="login-service"
        access-decision-manager-ref="accessDecisionManager">
....
    </http>



    <beans:bean id="userLoginService" class="my.test.service.impl.UserLoginService">
        <beans:property name="userProfileService" ref="userProfileService" />
    </beans:bean>




    <!-- Login message -->
    <beans:bean id="messageSource"
        class="org.springframework.context.support.ResourceBundleMessageSource">
        <beans:property name="basenames">
            <beans:list>
                <beans:value>mymessages</beans:value>
            </beans:list>
        </beans:property>
    </beans:bean>


</beans:beans>

我的 spring-security.xml

 function __construct($bar, $top){
    $this->$bar = $bar;
    $this->$top = $top;
 }

1 个答案:

答案 0 :(得分:0)

还有很多方法可以做到这一点。可行的方式取决于servlet-context.xml的方式。

首先,您只需从<beans:import resource="servlet-context.xml" />删除spring-security.xml

其他方式是删除它:

<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>WEB-INF/spring/appServlet/spring-security.xml</param-value>
</context-param>

而且:

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

并在spring-security.xml中包含对servlet-context.xml的导入。

一个好的做法是在多个应用程序上下文中分离您的配置,在applicationContext.xml中导入所有内容,并为servlet上下文设置特定的应用程序上下文,像这样:

applicationContext.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">

    <context:component-scan base-package="com.package" />

    <import resource="applicationContext-security.xml"/>
    <import resource="applicationContext-data.xml"/>

</beans>

applicationContext-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:p="http://www.springframework.org/schema/p"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
        http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
        http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security.xsd">

    <mvc:annotation-driven />

    <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"
        p:prefix="/WEB-INF/views/" p:suffix=".jsp" />

    <bean class="org.springframework.web.servlet.handler.SimpleMappingExceptionResolver" p:order="3" p:defaultErrorView="error" />

</beans>

在您的web.xml

<!-- spring servlet -->
<servlet>
    <servlet-name>springDispatcherServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>WEB-INF/applicationContext-servlet.xml</param-value>
    </init-param>
    <load-on-startup>0</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>springDispatcherServlet</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>classpath:META-INF/applicationContext.xml</param-value>
</context-param>