Question

有一些令牌

的代码

char word[30] = "This - is - my - cat";
const char s[2] = "- ";

   char *token;
   token = strtok(word, s);

while( token != NULL )
   {
      printf( " %s\n", token );

      token = strtok(NULL, s);}

那么如何从令牌中获取字符串？例如，我想抓住＆＃34;我的＆＃34;。

Answer 1

不确定你需要什么 - 这似乎是它 -

char *result[8];  // 8 is completely arbitrary here
char *token= strtok(word, s);
int i=0;
char keep[12]={0x0};
while( token != NULL )
   {
      printf( " %s\n", token );
      result[i++]=token;
      result[i]=NULL;
      token = strtok(NULL, s);
   }
// get one of the fields you want "my" == result[2]
   strcpy(keep, result[2]);

result []必须有足够的元素来处理代码将在其上抛出的任意数量的子字符串。

Answer 2

你的意思是这样的：

#include <string.h>
#include <stdio.h>

#define MAX_LENGTH_OF_A_TOKEN (10)

char word[30] = "This - is - my - cat";
const char s[3] = "- ";
const char str_my[3] = "my";
char buffer[MAX_LENGTH_OF_A_TOKEN];


int main()
{
    char *token;
    token = strtok(word, s);

    while( token != NULL )
    {
        strncpy(buffer, token, strlen(token)+1);
        {
            /* Now you have a local copy of your token in buffer. Do whatever you please with it.*/
            printf("%s\n", buffer);
        }

        token = strtok(NULL, s);
    }

    return 0;
}

从c中的标记中获取一些字符串

2 个答案: