Date Speed
____________________
01/01/2015 20
02/01/2015 30
03/01/2015 40
04/01/2015 0
05/01/2015 0
06/01/2015 0
07/01/2015 10
08/01/2015 20
需要这样的结果(其中speed = 0)
First-OccurrenceDate Last-OccurrenceDate
04/01/2015 06/01/2015
答案 0 :(得分:2)
试试这个:
SELECT MIN(Date) AS First-OccurrenceDate, MAX(Date) AS Last-OccurrenceDate
FROM MYTABLE
WHERE SPEED = 0
答案 1 :(得分:1)
试试这个:
select min([Date]) as [First-OccurrenceDate], max([Date]) as [Last-OccurrenceDate]
from yourtablename
where speed = 0