Question

我正在处理此登录视图。我希望用户在没有输入他/她的凭据时收到通知。例如，如果未输入用户名，则需要显示“请输入您的用户名”和密码。还有用户名和密码。到目前为止我的代码：

- (IBAction)testButton:(id)sender {

if (![self.usernameBox.text isEqualToString:@""] && ![self.passwordBox.text isEqualToString:@""])
{
    [self showLoginProcess:true];
    [[AuthSingleton getInstance] setDelegate:self];
    [[AuthSingleton getInstance] attemptLoginWithUsername:self.usernameBox.text andPassword:self.passwordBox.text];
} else
{
    NSLog(@"username or password is empty %@", kBaseURL);
}

由于

Answer 1

根据我的理解，你正在寻找一些逻辑来显示适当条件的正确信息。试试这可能会有所帮助。

if ([self.usernameBox.text length] > 0 && [self.usernameBox.text length] > 0)
{
    [self showLoginProcess:true];
    [[AuthSingleton getInstance] setDelegate:self];
    [[AuthSingleton getInstance] attemptLoginWithUsername:self.usernameBox.text andPassword:self.passwordBox.text];
} else
  {
    NSString *message;
    if ([self.usernameBox.text length] <= 0 && [self.passwordBox.text length] <=0) 
           message = @"Enter both the Fields";
     else if ([self.usernameBox.text length] <= 0 ) 
          message = @"Enter username";
     else if ([self.passwordBox.text length] <=0 ) 
           message = @"Enter password";

  UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Alert" message:message delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil, nil];
    [alert show];
}

Answer 2

嘿，你可以通过单一条件来做到这一点，

SimpleSAML_Error_Error: UNHANDLEDEXCEPTION
Backtrace:
1 C:\wamp\www\var\simplesamlphp\www\_include.php:37 (SimpleSAML_exception_handler)
0 [builtin] (N/A)
Caused by: Exception: Unexpected root node: [urn:oasis:names:tc:SAML:2.0:protocol]:Response
Backtrace:
2 C:\wamp\www\var\simplesamlphp\lib\SimpleSAML\Metadata\SAMLParser.php:305 (SimpleSAML_Metadata_SAMLParser::parseDescriptorsElement)
1 C:\wamp\www\var\simplesamlphp\lib\SimpleSAML\Metadata\SAMLParser.php:281 (SimpleSAML_Metadata_SAMLParser::parseDescriptorsString)
0 C:\wamp\www\var\simplesamlphp\www\admin\metadata-converter.php:11 (N/A)

向用户显示正确的消息

2 个答案: