duff设备不工作

时间:2015-05-27 09:15:20

标签: c loops duffs-device

我试图实施Duff设备,但它无法正常工作。它不会复制任何东西。我已经实现了原始版本和更清晰的版本:

void duff_function(int *a, int *b, int length)
{
    int n = (length + 7) / 8;
    switch(length % 8)
    {
        case 0: *a++ = *b++;    // I dereference, copy, and then increment the pointer, * > ++
        case 7: *a++ = *b++;
        case 6: *a++ = *b++;
        case 5: *a++ = *b++;
        case 4: *a++ = *b++;
        case 3: *a++ = *b++;
        case 2: *a++ = *b++;
        case 1: *a++ = *b++;
    }
    while ( --n > 0)
    {
        *a++ = *b++;
        *a++ = *b++;
        *a++ = *b++;
        *a++ = *b++;
        *a++ = *b++;
        *a++ = *b++;
        *a++ = *b++;
        *a++ = *b++;
    }

}

void send(int *to, int *from, int count)
{
        int n=(count+7)/8;
        switch(count%8){
           case 0: do{ *to = *from++;
           case 7:     *to = *from++;
           case 6:     *to = *from++;
           case 5:     *to = *from++;
           case 4:     *to = *from++;
           case 3:     *to = *from++;
           case 2:     *to = *from++;
           case 1:     *to = *from++;
                    }while( --n>0);
        }  
}

int main()
{
    int a[10] = {21, 34, 12, 64, 13, 9, 56, 54, 90, 1};
    int b[10] = {22};
    for (int i = 0; i < 10; ++i)
    {
       printf("%d, ", a[i]);
    }
    printf("\n");
    duff_function(a, b, 10);
    //send(a, b, 10);

    for(int i = 0; i < 10; ++i)
        printf("%d, ", b[i]);
    printf("\n");
    return 0;
}

输出结果为:

21, 34, 12, 64, 13, 9, 56, 54, 90, 1, 
22, 0, 0, 0, 0, 0, 0, 0, 0, 0, 

它不会复制任何东西。 在原始版本由于某种原因它不会增加指针,但我认为我应该增加它(我在我的函数中这样做)。

修改 据报道,我的代码中存在错误: 我改变了它:

send(b, a, 10);

但现在输出是:

1, 0, 0, 0, 0, 0, 0, 0, 0, 0,

编辑2 上次编辑以使代码工作:

duff_function(b, a);

2 个答案:

答案 0 :(得分:2)

您正在从b复制到a,但您希望从a复制到b

将每*a++ = *b++;更改为*b++ = *a++;

您也可以memcpy(b, a, length * sizeof *a);

答案 1 :(得分:0)

这个功能:

void send(int *to, int *from, int count)
{
    int n=(count+7)/8;
    switch(count%8)
    {
       case 0: do{ *to = *from++;
       case 7:     *to = *from++;
       case 6:     *to = *from++;
       case 5:     *to = *from++;
       case 4:     *to = *from++;
       case 3:     *to = *from++;
       case 2:     *to = *from++;
       case 1:     *to = *from++;
                }while( --n>0);
    }  
}

包含几个问题。

1) the while statement 
   places the majority of the switch case statements 
   at a different scope level from the first case statement.

2) stepping through the code
   int n = (10+7)%8 = 2
   switch(2)
      (jumping into the center of a do/while loop is 
      a very poor program practice)
      do{
      case 2: *to = *from++;
      case 1: *to = *from++; // which overlays the prior line
      } while( --n >0 ) // on first pass decrement 'n' to 1
      case 7:   overlays prior *to with from[2]
      case 6:   overlays prior *t0 with from[3]
      case 5:   ... from[4]
      case 4:   ... from[5]
      case 3:   ... from[6]
      case 2:   ... from[7]
      case 1"   ... from[8]
         while( --n >0 ) fails, exiting loop

      final result, *to = from[8]

这可能不是你想要做的事情