Question

我试图使用C和斯坦福便携式库（SPL）重新创建破砖者。我的initBricks函数的目标是在每行中添加5行ROWS和10个COLUMNS（总共50块砖）。当我运行此代码时，我的窗口只有10个砖的1行。由于某种原因，它不会输出其他4行。我的代码中没有看到我出错的地方。在创建每一行之后，我将y坐标（0,0是窗口的左上角）递增40。

// number of rows of bricks
#define ROWS 5

// number of columns of bricks
#define COLS 10

// height and width of bricks
#define BRICK_H 7.5
#define BRICK_W 35

// initializes window with grid of bricks
void initBricks(GWindow window)
{
    // set initial brick coordinates
    int x_coord = 2;
    int y_coord = 10;

    for (int i = 0; i < ROWS; i++)
    {
        // Create 10 columns of bricks
        for (int j = 0; j < COLS; j++)
        {
            // create a brick
            GRect brick = newGRect(x_coord, y_coord, BRICK_W, BRICK_H);
            setFilled(brick, true);
            setColor(brick, "RED");
            add(window, brick);

            // increment x coordinate for column spacing
            x_coord += 40;
        } 
        // increment y coordinate for row spacing
        y_coord += 40;  
    }
}

非常感谢任何帮助！

Answer 1

您需要重置每行的X坐标。

for (int i = 0; i < ROWS; i++)
{
    // Create 10 columns of bricks
    int x_coord = 2;                   // <---- move line down to here
    for (int j = 0; j < COLS; j++)
    {
        ...

Answer 2

您不能在外部for循环中重置x_coord变量，因此在第一行的末尾，您的x_coord为202，并且它开始编写下一行可能在窗外。只需在x_coord = 2;之后添加y_coord += 40;即可修复它。

for (int i = 0; i < ROWS; i++)
    {


       for (int j = 0; j < COLS; j++)
        {
            // create a brick
            GRect brick = newGRect(x_coord, y_coord, BRICK_W, BRICK_H);
            setFilled(brick, true);
            setColor(brick, "RED");
            add(window, brick);

            // increment x coordinate for column spacing
            x_coord += 40;
        } 
        // increment y coordinate for row spacing
        y_coord += 40;  
        //reset c coordinate
        x_coord = 2;

    }

Answer 3

如前所述，问题是X坐标。您可以通过将X，Y计算移动到for循环

来修复它

void initBricks(GWindow window)
{
    int row, col, x, y;

    for ( y = 10, row = 0; row < ROWS; row++, y += 40 )
        for ( x = 2, col = 0; col < COLS; col++, x += 40 )
        {
            GRect brick = newGRect(x, y, BRICK_W, BRICK_H);
            setFilled(brick, true);
            setColor(brick, "RED");
            add(window, brick);
        }
}

Answer 4

你应该在外循环体中初始化y坐标。因为每当你到达下一行时y坐标想要回到它的初始位置。

// number of rows of bricks
#define ROWS 5

// number of columns of bricks
#define COLS 10

// height and width of bricks
#define BRICK_H 7.5
#define BRICK_W 35

    // initializes window with grid of bricks
    void initBricks(GWindow window)
    {
        // set initial brick coordinates
        int x_coord = 2;

        for (int i = 0; i < ROWS; i++)
        {
        int y_coord = 10;
            // Create 10 columns of bricks
            for (int j = 0; j < COLS; j++)
            {
                // create a brick
                GRect brick = newGRect(x_coord, y_coord, BRICK_W, BRICK_H);
                setFilled(brick, true);
                setColor(brick, "RED");
                add(window, brick);

                // increment x coordinate for column spacing
                x_coord += 40;
            } 
            // increment y coordinate for row spacing
            y_coord += 40;  
        }
    }

C中的破砖者 - 增加砖块行

4 个答案: