我希望根据日期升序获取数据。代码以错误的格式获取数据,例如:
14/02/2014
16/01/2014
17/04/2013
,即日期排序基于" dd"只考虑月份和年份 代码在
之下string constr = @"Provider=Microsoft.ACE.OLEDB.12.0;Data Source=|DataDirectory|\Auto_Finance.accdb;Persist Security Info=False;";
OleDbConnection con = new OleDbConnection(constr);
con.Open();
string sql=@"select p.PName,p.hpno,c.Credit,C.Debit,c.Dates from Party_Det p inner join cd c on p.Loanno=c.Loanno order by c.Dates asc";
OleDbCommand cmd = new OleDbCommand(sql, con);
OleDbDataAdapter da = new OleDbDataAdapter(cmd);
DataTable dt = new DataTable();
da.Fill(dt);
dataGridView1.DataSource = dt;
con.Close();
但我想要下面的结果
17/04/2013
16/01/2014
14/02/2014
我使用c#作为前端,Microsoft Access作为前端。
答案 0 :(得分:1)
您的查询是
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStream;
public class Test {
public static void main(String[] args) throws IOException {
InputStream in=new FileInputStream("readme.my");
while (true) {
int byteRead=in.read();
if (byteRead==-1) break;
System.out.write(byteRead);
}
}
}
戈登说道
将“@"select p.PName,p.hpno,c.Credit,C.Debit,c.Dates from Party_Det p inner join cd c on p.Loanno=c.Loanno order by c.Dates desc"
”替换为“c.Dates desc
”
答案 1 :(得分:0)
试试这个:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="wrapper">
<div class="content">
<div class="subcontent">
<input type="text" class="first" id="first_1" />
<input type="text" class="second" id="second_1">
</div>
</div>
<div class="content">
<div class="subcontent">
<input type="text" class="first" id="first_2" />
<input type="text" class="second" id="second_2" />
</div>
</div>
<div class="content">
<div class="subcontent">
<input type="text" class="first" id="first_3" />
<input type="text" class="second" id="second_3" />
</div>
</div>
<div class="content">
<input type="text" class="first" id="first_4" />
</div>
</div>
<div class="content">
<input type="text" class="first" id="first_5" />
<input type="text" class="second" id="second_5" />
</div>
或者这个:
string sql = @"select p.PName,p.hpno,c.Credit,C.Debit,c.Dates from Party_Det p inner join cd c on p.Loanno=c.Loanno order by c.Dates desc";