Question

如何运行如下，给出if和else语句？

我等待肯定回复

def run():
    a=10
    b=20
    c=30
    if a==15 & b==20 & c==30:
        print('a is diff')
    else a==10 & b==20 & c==30:
        print ('same')
    else a==15 &  b==40 & c==30:
        print('a is diff')

Answer 1

您需要elif，而不能使用两个else。
此外，else一无所获。你应该替换& bij and。

def run():
    a = 10 
    b = 20 
    c = 30 
    if (a == 15) and (b == 20) and (c == 30): 
        print('a is diff') 
    elif (a == 10) and (b == 20) and (c == 30): 
        print ('same') 
    elif (a == 15) and (b == 40) and (c == 30): 
        print('a is diff')
    else:
        print('Other')

Answer 2

您应该使用elif代替else

Answer 3

我已经更正了您的代码，假设您希望代码示例返回“相同”。我已将else替换为elif，将按位运算符&替换为and。

def run(): 
    a=10 
    b=20 
    c=30 
    if a==15 and b==20 and c==30: 
        print('a is diff') 
    elif a==10 and b==20 and c==30: 
        print ('same') 
    elif a==15 and b==40 and c==30: 
       print('a is diff')

run()

如果和elif声明

3 个答案: