Question

让我说我的Android应用程序中有一个方法

updateArrayList(double data);

如何在5秒内运行该方法并在此之后停止？

Answer 1

你shuld尝试Thread.sleep（INT MILLIS）;并在try catch块中执行操作

Answer 2

使用计时器类这是完整的代码

import java.awt.Toolkit;
import java.util.Timer;
import java.util.TimerTask;
public class ReminderBeep {
  Toolkit toolkit;

  Timer timer;

  public ReminderBeep(int seconds) {
    toolkit = Toolkit.getDefaultToolkit();
    timer = new Timer();
    timer.schedule(new RemindTask(), seconds * 1000);
  }

  class RemindTask extends TimerTask {
    public void run() {
      System.out.println("Time's up!");
      toolkit.beep();
      //timer.cancel(); //Not necessary because we call System.exit
      System.exit(0); //Stops the AWT thread (and everything else)
    }
  }

  public static void main(String args[]) {
    System.out.println("About to schedule task.");
    new ReminderBeep(5);
    System.out.println("Task scheduled.");
  }
}

来自http://www.java2s.com/Code/Java/Development-Class/UsejavautilTimertoscheduleatasktoexecuteonce5secondshavepassed.htm

的代码

Answer 3

你可以试试这个：

    try { //you need the try and catch otherwise you get an error
        Thread.sleep(5000); //this is the actual waiting
    } catch (InterruptedException e) { //this can just be "Exception" it means that if the thread is told to start again, it wont cause an error.
        System.out.println("This code was told to start again.");
        //whatever you want to do if the code is told to start again during this.
    }

如何仅在五秒钟内运行方法

3 个答案: