Question

你好我有mysql的问题; 我想创建一个网络应用来管理收费;在此页面中，用户将创建一个月并添加月份费用我这里有三个表，表年（ID;年）表月（ID，月，id_year）和表费（ID，名称，描述，值，ID_month）当用户选择他想要的月份时，他添加费用并点击提交;月份应该添加到表月，同时费用被添加到表费用，问题是我需要月份ID将其添加到表费用，所以我在第一个“多个请求”之后选择它＃39;完成然后我尝试通过添加月份ID来更新表费用，但它不起作用，我收到此错误＆＃39;命令不同步;你现在不能运行这个命令＆＃39; 这里是代码请帮我找一个解决方法怎么做plz谢谢

//--test POST vars
    if ($_SERVER['REQUEST_METHOD'] == 'POST') {
        //test inputs from functions.php
        $month = test_input($_POST['month']);

        //year from url GET
        $year = 2000;
        $sql_year = "SELECT ID FROM year WHERE year = '" . $year . "' ";
        $year_result = mysqli_query($conn, $sql_year);
        $year_fetch = mysqli_fetch_assoc($year_result);
        $year_ID = $year_fetch['ID'];
        //check if month already exist
        $check_month = "SELECT ID FROM month WHERE month = '" . $month . "' AND year_ID = '" . $year_ID . "'";
        $month_result = mysqli_query($conn, $check_month);
        if (mysqli_num_rows($month_result) == 1) {
            //if it exist do nothing but set error msg
            $msgerr = $lang['addmonth-error-monthexist'];
        } else {
            //insert month and year ID in month table
            $sql = "INSERT INTO month (month, year_ID) VALUES ('" . $month . "','" . $year_ID . "');";

            //depending on how many charges were set do the test inputs and add to sql db
            foreach ($_POST['charge'] as $iq => $val) {

                $charge[$iq] = test_input($val);
                $description[$iq] = test_input($_POST['description'][$iq]);
                $value[$iq] = test_input($_POST['value'][$iq]);

                $sql .= "INSERT INTO charges (designation, description, value) VALUES ('" . $charge[$iq] . "','" . $description[$iq] . "','" . $value[$iq] . "');";

            }

            if ($reslult = mysqli_multi_query($conn, $sql) === TRUE) {

                $msgs = $lang['message_succ_datasaved'];
            } else {
                $msge = $lang['message_errorgen'];
            }

            //Select the add month's ID
                $msql= "SELECT ID FROM month WHERE month = '".$month."' && year_ID = '".$year_ID."' ";
                $month_idqu = mysqli_query($conn,$msql);
                if (!$month_idqu) {
    echo 'MySQL Error: ' . mysqli_error($conn);
    exit;
}
                $month_id = mysqli_fetch_assoc($month_idqu);


                $charge_up = mysqli_query($conn, "UPDATE charges SET month_ID = '".$month_id."' WHERE ID = '".$charge_id."' ");
        }//end else if month exist
    }//end if request method

php，mysql错误：命令不同步

0 个答案: